A person’s blood type depends on the type of protein marker, called an , found on the cell membranes of the red blood cells.

A rear window defroster consists of a long, flat wire bonded to the inside surface of the window. When current passes through th

GenaCL600 [577]

Answer:

$\rho=1.8\times 10^{-8}\Omega.m$

Explanation:

Given:

width of the wire, $w=1.8\ mm=1.8\times 10^{-3}\ m$

thickness of the flat wire, $d=0.12\ mm=1.2\times 10^{-4}$

length of the wire, $l=12\ m$

voltage across the wire, $V=12\ V$

current through the wire, $I=12\ A$

Now the net resistance of the wire:

using ohm's law

$R=\frac{V}{I}$

$R=\frac{12}{12}$

$R=1\ \Omega$

We have the relation between the resistivity and the resistance as:

$R=\rho.\frac{l}{a}$

where:

a = cross sectional area of the wire

$\rho =$ resistivity of the wire material

$1=\rho\times \frac{12}{1.8\times 10^{-3}\times 1.2\times 10^{-4}}$

$\rho=1.8\times 10^{-8}\Omega.m$

4 0

3 years ago

Find the frequency, if the amplitude of a 3000g object in simple harmonic motion is 1000cm and the maximum speed of the object i

Oksana_A [137]

Answer:

A = 10 m amplitude

m = 3 kg mass of object

Vm = 5 m/s

w A = Vm where w = omega

w = 2 * pi * f

2 * pi * f 10 = 5

f = 5 / (20 * pi) = .0796 / sec

7 0

2 years ago

How much time does it take for a plane To fly 5000 miles if the plane travels a speed of 500 miles per hour?

Vitek1552 [10]

Answer:

10 hours

Explanation:

If the plane flies at 500 miles per hour, it flies 500 miles every hour. So, to find out how many hours it will take to fly 5000, you simply do 5000/500.

5 0

3 years ago

Read 2 more answers

What do we call a change in the car’s speed or direction?<br><br><br> Help!!

zhuklara [117]

The answer for this question is acceleration

8 0

3 years ago

Read 2 more answers

A 12.0N force with a fixed orientation does work on a

kvasek [131]

Answer:

(a) $\theta=62.31^{\circ}$

(b) $\theta=117.68^{\circ}$

Explanation:

It is given that,

Force acting on the particle, F = 12 N

Displacement of the particle, $d=(2.00i -4.00j+3.00k)\ m$

Magnitude of displacement, $d=\sqrt{2^2+4^2+3^2}= 5.38\ m$

(a) If the change in the kinetic energy of the particle is +30 J. The work done by the particle is given by :

$W=Fd\ cos\theta$

$\theta$ is the angle between force and the displacement

According to work energy theorem, the charge in kinetic energy of the particle is equal to the work done.

So,

$cos\theta=\dfrac{W}{Fd}$

$cos\theta=\dfrac{+30\ J}{12\times 5.38}$

$\theta=62.31^{\circ}$

(b) If the change in the kinetic energy of the particle is (-30) J. The work done by the particle is given by :

$cos\theta=\dfrac{W}{Fd}$

$cos\theta=\dfrac{-30\ J}{12\times 5.38}$

$\theta=117.68^{\circ}$

Hence, this is the required solution.

8 0

3 years ago