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3 years ago

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A closed rigid tank contains water initially at 10,000 kPa and 520ºC and is cooled to a final temperature of 270° C. Determine t

he final pressure of the water.

1 answer:

jasenka [17]3 years ago

5 0

Answer:

final pressure is 6847.41 kPa

Explanation:

given data:

$P_1 = 10,000 kPa$

$T_1 =520\ degree\ celcius = 793 K$

$T_2 = 270 degree celcius = 543 K$

as we can see all temperature are more than 100 degree, it mean this condition is refered to superheated stream

for ischoric process we know that

$\frac{P_1}{T_1} =\frac{P_2}{T_2}$

$\frac{10*10^6}{793} = \frac{P_2}{543}$

$P_2 = 6.84741*10^6 Pa$

final pressure is 6847.41 kPa

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Answer:

Following are the proving to this question:

Explanation:

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using the energy equation for entry and exit value :

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where

$\to p_0=p_1=0\\\\\to Z_0=Z_1=H\\\\\to v_0=0\\\\AV =A_1V_1 \\\\\to V=(\frac{D_1}{D})^2 V_1\\\\\to V^2=(\frac{D_1}{D})^4 V^{2}_{1}$

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$= \frac{1}{(2f (\frac{l}{D}) )} \ V^{2}_{1}\\$

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3 years ago

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3 years ago

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3 years ago