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3 years ago

Look at this set of ordered pairs.

Mathematics

1 answer:

sasho [114]3 years ago

7 0

3,3,4,4,7,11,11,12,13

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A^-5b^-4/a^-13b^8 a. a^8 b^12 b. ab^5 c. a^8/b^12 d.b^-9/b^-5

lord [1]

If you would like to solve a^(-5)b^(-4) / a^(-13)b^8, you can do this using the following steps:

a^(-5)b^(-4) / a^(-13)b^8 = a^13 / a^5b^4b^8 = a^8 / b^12

The correct result would be c. a^8 / b^12.

5 0

3 years ago

The equation the quantity of x plus 20 over 2 = 3x represents when two tutoring services with different rate plans charge the sa

Inga [223]

None of the options give the same fees for a session of x hours.

Given,
x + 20/2 = 3x
when two tutoring services with different rate plans charge the same fees for a session of x hours.

<h3>What is arithmetic?</h3>

In mathematics, it deals with numbers of operations according to the statements.

x + 20/2 = 3x
x + 10 = 3x

A) x= 10
10 + 10 = 3*10
20 ≠ 30

B) x=4
4 + 10 = 3 * 4
14 ≠ 12

C) x= -14
-14 + 10 = 3 * -14
-4 ≠ 42

D) x=-17
- 17 + 10 = 3 * - 17
-7 ≠ -51

Here, none of the options give the same fees for a session of x hours.

Thus, none of the options give the same fees for a session of x hours.

Learn more about arithmetic here:

brainly.com/question/14753192

#SPJ1

8 0

1 year ago

Mike paid $11.71 total

yan [13]

Answer:

Bill received 13.68 change back.

Step-by-step explanation:

20-6.32=13.68

7 0

3 years ago

Read 2 more answers

If sin 20 degree=a and cos20 degree=b then which of the following represents the correct value of sin 70 degree in terms of a an

Scorpion4ik [409]

ANSWER

3) b

EXPLANATION

Given that:

$\sin(20 \degree) = a$

and

$\cos(20 \degree) = b$

Recall that the sine and cosine functions are equal for complementary angles.

This implies that,

$\sin(70 \degree) = \cos(20 \degree)$

$\sin(70 \degree) = b$

5 0

3 years ago

Someone help me please :(

Aleksandr-060686 [28]

9514 1404 393

Answer:

A. ∠EAG and ∠BAC

Step-by-step explanation:

Vertical angles share a vertex and have opposite rays for sides.

Rays AE and AB are opposite; rays AG and AC are opposite. These are the only pairs of opposite rays in the figure, so the vertical angles must be constructed from one of the rays of the first pair and one of the rays of the second pair. ∠EAG and ∠BAC are a pair of vertical angles.

The other pair is ∠EAC and ∠BAG.

5 0

2 years ago