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3 years ago

How is science controlled by the governerment

Physics

2 answers:

Vedmedyk [2.9K]3 years ago

6 0

Answer:

the government's use and control of science. To clarify, I live in the U.S. I'm only interested in how the U.S. government dictates science. If you have any information or links that could educate me on this topic, I would be appreciative.

Explanation:

SCORPION-xisa [38]3 years ago

4 0

Answer:

Science is controlled by the government since, in addition to the fact that any scientific advance requires government financial support, it is constantly monitored, in order to "avoid" dangerous advances.

Explanation:

Unfortunately, a great scientific advance can require many funds, which is why scientists usually go to private companies or the government for it to be financed, but even more so, when a scientist carries out a study financed by himself, which leads to an advance a novel scientist, is constantly monitored by governmental entities to identify whether or not such progress represents a danger to the nation or if they must appropriate it.

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TRUE OR FALSE Light can travel through materials that you cannot see through, like wood or aluminum foil.

Keith_Richards [23]

i think its uhh......tralse

8 0

3 years ago

A playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.400 rev

saw5 [17]

Answer:

The final angular velocity is rev/s is 0.293 rev/s.

Explanation:

Given;

mass of the merry-go-round, m₁ = 120 kg

radius of the merry-go-round, r = 1.8 m

initial angular velocity, ω = 0.4 rev/s

mass of the child, m₂ = 22 kg

Apply the principle of conservation angular momentum to determine the final angular velocity;

$I_i= I_f\\\\\frac{1}{2} m_1r^2 \omega _i = \frac{1}{2} m_1r^2 \omega _f + m_2r^2 \omega _f\\\\ \frac{1}{2} m_1r^2 \omega _i =( \frac{1}{2} m_1r^2 + m_2r^2 )\omega _f\\\\\omega _f = \frac{ \frac{1}{2} m_1r^2 \omega _i}{\frac{1}{2} m_1r^2 + m_2r^2} \\\\\omega _f = \frac{ \frac{1}{2} m_1 \omega _i}{\frac{1}{2} m_1 + m_2}\\\\\omega _f = \frac{0.5 \ \times \ 120\ kg \ \times \ 0.4\ rev/s}{0.5 \ \times 120\ kg \ \ + \ \ 22 \ kg} \\\\\omega _f = 0.293 \ rev/s\\$

Therefore, the final angular velocity is rev/s is 0.293 rev/s.

3 0

3 years ago

A car travels 300 km in the first 3 hours of a trip. Then it hits traffic and travels only 60 km during the last hour. What is t

Nadusha1986 [10]

Question

A car travels 300 km in the first 3 hours of a trip. Then it hits traffic and travels only 60 km during the last hour. What is the average speed of the of the car?

300 + 60 = 360 Km (total travel)

3 + 1 = 4 hours (total time)

360 : 4 = 90

C.) 90 Km/h is your answer

6 0

3 years ago

Calculate the force required to accelerate a 600 g ball from rest to 14 m/s in 0.1 s.

Evgen [1.6K]

Statement:

A force is required to accelerate a 600 g ball from rest to 14 m/s in 0.1 s.

To find out:

The force required to accelerate the ball.

Solution:

Mass of the ball (m) = 600 g = 0.6 Kg
Initial velocity (u) = 0 m/s [it was at rest]
Final velocity (v) = 14 m/s
Time (t) = 0.1 s

Let the acceleration be a.
We know the equation of motion,
v = u + at

Therefore, putting the values in the above formula, we get
14 m/s = 0 m/s + a × 0.1 s
or, 14 m/s ÷ 0.1 s = a
or, a = 140 m/s²

Let the force be F.
We know, the formula : F = ma

Putting the values in the above formula, we get
F = 0.6 Kg × 140 m/s²
or, F = 84 N

Answer:

The force required to accelerate the ball is 84 N and this force acts along the direction of motion.

Hope you could understand.

If you have any query, feel free to ask.

5 0

2 years ago

Suppose that the potential energy of a particle constrained

denpristay [2]

The graph of the potential energy pass through zero origin, cuts across positive x-axis and negative x-axis.

<h3>Slope of the graph</h3>

The slope of the graph when the potential energy of a particle constrained in on x-axis is determined as follows;

F = -dU/dx

-dU = Fdx

dU = -Fdx

U = -∫(kx + ax³)dx

U = kx²/2 - ax⁴/4

When, x = 0, U = 0

When U = 0;

$x = \pm \sqrt{\frac{2k}{a} }$

The graph of the potential energy pass through zero origin, cuts across positive x-axis and negative x-axis.

Complete question is below:

Suppose that the potential energy of a particle constrainedon x-axis and subjected to a force in the same direction, at a fuction of F(x) = -kx + ax³.

Find the functional form of the potential energy.

Learn more about potential energy here: brainly.com/question/1242059

#SPJ1

4 0

2 years ago