Answer:
yes
Explanation:
1.98×10 m/s
you can use a physics text
I remember but am not sure
3.00 × 10 m/s
I think you do 10 ×10 in 8 places for both them you do the rest
Answer:
r = 1.56 m
Explanation:
B = μ₀I/2πr
r = μ₀I/2πB
I = 9.00 / 52.0 = 0.173 A
μ₀ = 4πe-7 T•m/A
r = 4πe-7(0.173)/2π(2.22e-8)
r = 2e-7(0.173)/(2.22e-8)
r = 1.5592... ≈ 1.56 m
Answer:
D 5 V
Explanation:
Without seeing the whole circuit it is impossible to say for certain.
However the simplest circuit would produce a value of
FV = IR = 0.25(20) = 5 v
Answer: unknown so the second one
I hope this helps you with your stuff
Answer:
U2 = 47.38m/s = initial velocity of B before impact
Explanation:
An example of the diagram is shown in the attached file because of missing angle of direction in the question
Mass A, B are mass of cars
A = 1965
B =1245
U1 = initial velocity of A = 52km/hr
U2 = initial velocity of B
V = common final velocity of two cars
BU2 = (A + B)*V sin ¤ ...eq1 y plane
AU1 = (A + B) *V cos ¤ ....equ 2plane
From equ 2
V = AU1/(A + B)*cos ¤
Substitute V into equation 1
We have
U2 = (AU1/B)tan ¤ where ¤ = angle of direction which is taken to be 30°
Substitute all parameters to get
U2 = (1965/1245)*52 * tan 30°
U2 = 47.38m/s