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Marina86 [1]
3 years ago
6

I really need help with this before 5:10

Chemistry
1 answer:
Alexxandr [17]3 years ago
3 0

( I got you fam. )

Answer ( assuming that your brother is doing 4,000 grams and not 4 grams ) :

around 8 pound's

Explanation:

1 gram = around 0.002 gram's

4,000 x 0.002 = 8

8 pound's :-)

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Help pls I will give brainliest!
yKpoI14uk [10]

Answer:

The answer is D, I would type it out but it is to long and I'm kind of lazy, but anyways! Your answer is D

Hope This Helps!

7 0
3 years ago
Gravity on Earth is 9.8 m/s2, and gravity on the Moon is 1.6 m/s2.
Ivanshal [37]

Answer:

Mass is the same but it weights 64 Newtons

Explanation:

First of Mass is the same in any sort of gravity. Now let's calculate weight

W = MG

where W = Weight

M = Mass

G = Gravity

W = (40kg)(1.6)

W = 64

Sorry for the spelling mistakes, hope this helps

7 0
3 years ago
Read 2 more answers
In which layer of the ocean do surface currents flow?
Marat540 [252]

Answer:

ooh sorry, but will this help you now:

Ocean dynamics define and describe the motion of water within the oceans. Ocean temperature and motion fields can be separated into three distinct layers: mixed (surface) layer, upper ocean (above the thermocline), and deep ocean. Ocean currents are measured in sverdrup (sv), where 1 sv is equivalent to a volume flow rate of 1,000,000 m (35,000,000 cu ft) per second.

Surface currents, which make up only 8% of all water in the ocean, are generally restricted to the upper 4…

Explanation:

Hope this helps :)

8 0
3 years ago
Dry ice is solid carbon dioxide. Instead of melting, solid carbon dioxide sublimes according to the following equation: CO2(s)→C
GREYUIT [131]

Answer:

m=8.79kg

Explanation:

First of all we need to calculate the heat that the water in the cooler is able to release:

Q=\rho * V*Cp*\Delta T

Where:

  • Cp is the mass heat capacity of water
  • V is the volume
  • \rho is the density

Q=1 g/cm^3 *15000 cm^3*4.184 \frac{J}{g*^{\circ}C}*(10-90)^{\circ}C

Q=-5020800 J=-5020.8 kJ

To calculate the mass of CO2 that sublimes:

-Q=\Delta H_{sub}*m

Knowing that the enthalpy of sublimation for the CO2 is: \Delta H_{sub}=571 kJ/kg

5020.8 kJ=571 kJ/kg*m

m=\frac{5020.8 kJ}{571 kJ/kg}=8.79kg

6 0
3 years ago
Fission and Fusion of Atomic Nuclei:
bogdanovich [222]

Answer:

C B A D

Explanation:

6 0
4 years ago
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