The amount, in grams, of ethanol needed to prepare 268 grams of a 9.76 M solution of ethanol in water will be 120.50 grams
<h3>Solution preparation</h3>
In order to prepare 268 grams of solution, 268 mL of water would be needed because 1 mL of water weighs 1 gram.
Since we now know the volume of solution that we want to prepare, the amount of solute (ethanol) that would be required in order to make a solution of 9.76 M will be:
Mole required = 9.76 x 268/1000 = 2.62 moles
Mass of 2.62 moles ethanol = 2.62 x 46.07 = 120.50 grams
More on solution preparation can be found here: brainly.com/question/14667249
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Well scientific laws are really laws! You can't change a scientific law and laws can be facts as well. Hope this helps!
1. 4 electrons
2. Ernest Rutherford
3. Discovered the existence of a center of atom
4. 17 protons
Answer:
2
Explanation:
In calcium oxide, the calcium is electropositive in nature and to fulfil its octet, the calcium atoms lose two electrons to form the calcium cations whose valency is 2, hence the corresponding anion, i.e. the oxide anion must also have valency 2 to balance the positive charge on the calcium cation.
Hope this helps... 0_0