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Citrus2011 [14]
3 years ago
6

The solubility of potassium chloride __ as its temperature __.

Chemistry
1 answer:
Gre4nikov [31]3 years ago
8 0

The solubility of potassium chloride <u>increase</u><u>s</u><u> </u>as its temperature <u>increases</u><u>.</u>

  • <em>When</em><em> </em><em>the</em><em> </em><em>temperature</em><em> </em><em>of</em><em> </em><em>water</em><em> </em><em>increases</em><em> </em><em>the</em><em> </em><em>particles</em><em> </em><em>of</em><em> </em><em>KCl</em><em> </em><em>(</em><em>Potassium</em><em> </em><em>chloride</em><em>)</em><em> </em><em>starts</em><em> </em><em>to</em><em> </em><em>move</em><em> </em><em>freely</em><em>.</em><em> </em><em>Thus</em><em>,</em><em> </em><em>Resulting</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>increased</em><em> </em><em>solubility</em><em>.</em><em>.</em><em>.</em>
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3 years ago
What is alchemy?
Naily [24]

Answer:  A. An early form of chemistry that people used to try to turn metal

into gold.

Explanation:

Alchemy is indeed an early form of chemistry in which people try to turn metal into gold.

6 0
3 years ago
HELP PLSSS ASAP!! IF ANYONE KNOWS
torisob [31]

Answer:

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Explanation:

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3 0
3 years ago
What is the molar mass of 4.23 g of an elemental gas in a 2.5L container at 282K and 1.4 atm?
balu736 [363]

Answer:

27.98g/mol

Explanation:

Using ideal gas law equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

T = temperature (K)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

According to the information given:

V = 2.5L

P = 1.4 atm

T = 282K

n = ?

Using PV = nRT

n = PV/RT

n = 1.4 × 2.5/0.0821 × 282

n = 3.5/23.1522

n = 0.151mol

Using the formula to calculate molar mass of the elemental gas:

mole = mass/molar mass

Molar mass = mass/mole

Molar mass = 4.23g ÷ 0.151mol

Molar mass = 27.98g/mol

6 0
3 years ago
How many moles are in 60.0 grams of water?
Mashutka [201]
<h3>Answer:</h3>

3.33 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

60.0 g H₂O (Water)

<u>Step 2: Identify Conversions</u>

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 60.0 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})
  2. Multiply:                             \displaystyle 3.32963 \ mol \ H_2O

<u>Step 4: Convert</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.32963 mol H₂O ≈ 3.33 mol H₂O

5 0
3 years ago
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