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Citrus2011 [14]
3 years ago
6

The solubility of potassium chloride __ as its temperature __.

Chemistry
1 answer:
Gre4nikov [31]3 years ago
8 0

The solubility of potassium chloride <u>increase</u><u>s</u><u> </u>as its temperature <u>increases</u><u>.</u>

  • <em>When</em><em> </em><em>the</em><em> </em><em>temperature</em><em> </em><em>of</em><em> </em><em>water</em><em> </em><em>increases</em><em> </em><em>the</em><em> </em><em>particles</em><em> </em><em>of</em><em> </em><em>KCl</em><em> </em><em>(</em><em>Potassium</em><em> </em><em>chloride</em><em>)</em><em> </em><em>starts</em><em> </em><em>to</em><em> </em><em>move</em><em> </em><em>freely</em><em>.</em><em> </em><em>Thus</em><em>,</em><em> </em><em>Resulting</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>increased</em><em> </em><em>solubility</em><em>.</em><em>.</em><em>.</em>
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The four major attractive forces between particles are ionic bonds, dipole-dipole attractions, hydrogen bonds, and dispersion fo
natima [27]

Answer with Explanation:

Ionic bond:It is that type of bond which formed between negative and positive ions.

Hydrogen bonding:Hydrogen bonding formed between hydrogen and high electronegative elements.

Dispersion force:It is weakest intermolecular force.It is temporary attractive force.When electrons of two adjacent atoms occupy positions that make the atoms temporary dipoles.

NaCl: In which Na is positive ion and Cl is negative ion.

Therefore, NaCl is ionic.

HF:F is highest electronegativ elements.

HF:Hydrogen bonding

HCl: Hydrogen bonding

F_2:Dispersion

4 0
3 years ago
An oxide of nitrogen contains 30.45 mass % N.
N76 [4]

An oxide of nitrogen contains 30.45 mass % N, if the molar mass is 90± 5 g/mol the molecular formula is N₂O₄.

<h3>What is molar mass?</h3>

The molar mass of a chemical compound is determined by dividing its mass by the quantity of that compound, expressed as the number of moles in the sample, measured in moles. A substance's molar mass is one of its properties. The compound's molar mass is an average over numerous samples, which frequently have different masses because of isotopes.

<h3>How to find the molecular formula?</h3>

The whole-number multiple is defined as follows.

Whole-number multiple = \frac{molar mass (g/mol)}{empirical formula mass (g/mol)}

The empirical formula mass is shown below.

Mw of empirical formula = Mw of N+ 2 x (Mw of O)

                                      = 14.01 g/mol + 2 x (16.00 g/mol)

                                      = 46.01 g/mol

With the given molar mass or the molecular formula mass, we can get the whole-number multiple for the compound.

Whole-number multiple = \frac{90 g/mol }{46.01 g/mol} ≈ 2

Multiplying the subscripts of NO2 by 2, the molecular formula is N(1x2)O(2x2)= N2O4.

To learn more about molar mass visit:

brainly.com/question/12127540

#SPJ4

5 0
2 years ago
Chemistry!! Please help asap!! Will mark brainiliest!!
Whitepunk [10]
<h2>Answer:</h2><h3>Part 1. </h3>

Option B is correct option.

The half-reaction 2MnO2 + H2O + 2e- Mn2O3 is missing  OH- ions.

Explanation:

Full equation:

                                          2MnO2 + H2O + 2e-  → Mn2O3 + 2OH-

<h3>Part 2:</h3>

The option B which is Mg is stronger reducing agent than Ag is correct option.

Explanation:

Equation:

                               Mg(s) + 2Ag+ (aq) → Mg2+ (aq) + 2Ag(s)

According to equation Mg converts to Mg+2 which means it gives to electron to reduce Ag. So it act as an reducing agent.

<h3>Part 3:</h3>

The correct option is B. Which is  5, 1, 8, 5, 1, 4.

Explanation:

Full equation :

                  5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) --> 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O (l)


<h3 />

5 0
3 years ago
3
Wewaii [24]

Answer: 0.0450 moles of CaCl_2

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

\text{Number of moles of} CaCl_2=\frac{5.00g}{110.98g/mol}=0.0450moles

Thus there are 0.0450 moles of CaCl_2

6 0
3 years ago
A 31.0 mL sample of 0.624M perchloric acid is titrated with a 0.258M sodium hydroxide solution.
levacccp [35]

Answer:

0.0922 M

Explanation:

The problem first states that the titration is made using NaOH, and later asks about the addition of KOH. I'm going to assume NaOH was used throughout the whole problem. The result does not change if it was KOH instead.

The reaction that takes place is:

  • HClO₄ + NaOH → NaClO₄ + H₂O

First we <u>calculate how many HClO₄ moles are there in the sample</u>, using the <em>given molarity and volume</em>:

  • 0.624 M * 13.0 mL = 8.11 mmol HClO₄

Then we <u>calculate how many NaOH moles were added</u>:

  • 0.258 M * 15.0 mL = 3.87 mmol NaOH

Now we calculate how many HClO₄ remained after the reaction:

  • 8.11 - 3.87 = 4.24 mmol HClO₄

As <em>HClO₄ is a strong acid</em>, 4.24 mmol HClO₄ = 4.24 mmol H⁺

Finally we <u>calculate the molarity of H⁺</u>, using the<em> calculated number of moles and final volume</em>:

  • Final volume = 31.0 mL + 15.0 mL = 46.0 mL
  • 4.24 mmol / 46.0 mL = 0.0922 M
5 0
3 years ago
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