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3 years ago

Which of the following describes a mixture?

1 answer:

4 0

The correct answer is C. Explanation: a mixture is the physical combination of two or more substances who’s identities are retained. Therefore, c is correct.

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What is the first anmial

denpristay [2]

The first animal was called the comb jelly

8 0

3 years ago

You read through a site about inventions that contains the following paragraph:

Ludmilka [50]

The correct option is C. The paragraph is biased, not taking into consideration the other great inventions that have been made. The information given are vague, over generalised, without providing any evidence to support its claims. They are blanket statementso and are not useful at all.

6 0

3 years ago

You have a sample of each of the following five metals, with the mass and density

Sindrei [870]

Answer:

E) Silver, mass = 420 g, d = 10.5 g/cm.

Explanation:

Hello,

In this case, since the density is defined by:

$\rho =\frac{m}{V}$

Given the mass and density, we compute the volume via:

$V=\rho *m$

Thus, for each vase we have:

A) $V=135g*2.7g/cm^3=364.5cm^3$

B) $V=305g*8.92g/cm^3=2720.6cm^3$

C) $V=240g*7.86g/cm^3=1886.4cm^3$

D) $V=75g*1.74g/cm^3=130.5cm^3$

E) $V=420g*10.5g/cm^3=4410cm^3$

In such a way, the largest volume corresponds to E) Silver, mass = 420 g, d = 10.5 g/cm.

Best regards.

7 0

3 years ago

A gas that was cooled to 200 Kelvin has a volume of 65.8 L. If its initial volume was 132.4 L, what was its initial temperature?

Mandarinka [93]

Answer:

Initial temperature, T1 = 99.4 Kelvin

Explanation:

<u>Given the following data;</u>

Initial volume, V1 = 65.8 Litres
Final temperature, T2 = 200 Kelvin
Final volume, V2 = 132.4 Litres

To find the initial temperature (T1), we would use Charles' law;

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles' law is given by the formula;

$\frac {V}{T} = K$

$\frac {V_{1}}{T_{1}} = \frac {V_{2}}{T_{2}}$

Making T1 as the subject formula, we have;

$T_{1} = \frac {V_{1}T_{2}}{V_{2}}$

Substituting the values into the formula, we have;

$T_{1} = \frac {65.8 * 200}{132.4}$

$T_{1} = \frac {13160}{132.4}$

<em>Initial temperature, T1 = 99.4 Kelvin</em>

6 0

3 years ago

Any tips for Chemistry Practical? Im taking my Olevel practical tmr. Anyone?

garik1379 [7]

Answer:

re-do test if needed

Explanation:

if you're done early for the practical, check your answers back to the solutions. If feel the need to re-check if the answers are somewhat correct, re-do the steps :) all the best!

3 0

4 years ago