All categories

4 years ago

Which statement describes the Arrhenius interpretation of acids and bases

Chemistry

2 answers:

KIM [24]4 years ago

8 0

<span>it is limited to situations that involve aqueous solutions of specific compounds

I hope this helps</span>

kobusy [5.1K]4 years ago

4 0

Answer:

It is limited to situations that involve aqueous solutions or specific compounds.

Explanation:

the answer was correct on edge

You might be interested in

How many grams in 6.20 x 10^25 atoms of bromine (Br) ? image attached , will give brainliest

Deffense [45]

Answer:

8239.2g

Explanation:

Given parameters:

Number of atoms in Br = 6.2 x 10²⁵atoms

Unknown:

Mass of Br = ?

Solution:

From mole concepts, we know that:

1 mole of a substance contains 6.02 x 10²³ atoms/mol

Molar mass of Br = 80g/mol

6.2 x 10²⁵atoms x $\frac{1}{6.02 x 10^{23} }$ $\frac{mol}{atoms}$ x 80 x $\frac{g}{moles}$

= 8239.2g

8 0

3 years ago

A water bottle has a mass of 14.0g. Given a density of 1.38g/cm^3, what is the volume of the plastic used to make the water bott

Kipish [7]

Answer:

$\boxed{\sf Volume \ of \ plastic \ used = 10.14 \ cm^3}$

Given:

Mass = 14.0 g

Density ( $\rho$ ) = 1.38 g/cm³

To Find:

Volume (V)of the plastic used to make water bottle

Explanation:

Formula:

$\boxed{ \bold{Density \ (\rho) = \frac{Mass \ (m)}{Volume \ (V)}}}$

Substituting value of m & density in the formula:

$\sf \implies 1.38 = \frac{14.0}{V} \\ \\ \sf \implies V = \frac{14.0}{1.38} \\ \\ \sf \implies V = 10.14 \ cm^3$

$\therefore$

Volume of the plastic used to make water bottle = 10.14 cm³

6 0

3 years ago

Give an example of an unbalanced force.

Margarita [4]

An example is when on a seesaw if a kid is on one side and an adult is on the other then it is unbalanced because the adult weighs more

5 0

3 years ago

Read 2 more answers

A chemist has to prepare 250.0 mL of a 0.300 M Na2SO4(aq) solution. What mass, in grams, of sodium sulfate (formula mass 142.05

Sedbober [7]

The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g

<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>

Volume = 250 mL = 250 / 1000 = 0.25 L
Molarity = 0.3 M

Mole of Na₂SO₄ =?

Mole = Molarity x Volume

Mole of Na₂SO₄ = 0.3 × 0.25

Mole of Na₂SO₄ = 0.075 mole

<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>

Molar mass of Na₂SO₄ = 142.05 g/mol
Mole of Na₂SO₄ = 0.075 mole

Mass of Na₂SO₄ =?

Mass = mole × molar mass

Mass of Na₂SO₄ = 0.075 × 142.05

Mass of Na₂SO₄ = 10.65 g

Thus, 10.65 g of Na₂SO₄ is needed to prepare the solution.

Learn more about molarity:

brainly.com/question/15370276

6 0

2 years ago

A sample of xenon occupies a volume of 736 mL at 2.02 atm and 1 °C. If the volume is changed to 416 mL and the temperature is ch

kozerog [31]

Answer:

$\large \boxed{\text{4.63 atm}}$

Explanation:

To solve this problem, we can use the Combined Gas Laws:

$\dfrac{p_{1}V_{1} }{n_{1}T_{1}} = \dfrac{p_{2}V_{2} }{n_{2}T_{2}}$

Data:

p₁ = 2.02 atm; V₁ = 736 mL; n₁ = n₁; T₁ = 1 °C

p₂ = ?; V₂ = 416 mL; n₂ = n₁; T₂ = 82 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = ( 1 + 273.15) K = 274.15 K

T₂ = (82 + 273.15) K = 355.15 K

(b) Calculate the new pressure

$\begin{array}{rcl}\dfrac{p_{1}V_{1}}{n_{1} T_{1}} & = & \dfrac{p_{2}V_{2}}{n_{2} T_{2}}\\\\\dfrac{\text{2.02 atm}\times \text{736 mL}}{n _{1}\times \text{274.15 K}} & = &\dfrac{p_{2}\times \text{416 mL}}{n _{1}\times \text{355.15 K}}\\\\\text{5.423 atm} & = &1.171{p_{2}}\\p_{2} & = & \dfrac{\text{5.423 atm}}{1.171}\\\\ & = & \textbf{4.63 atm} \\\end{array}\\\text{The new pressure will be $\large \boxed{\textbf{4.63 atm}}$}}$

6 0

3 years ago