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gizmo_the_mogwai [7]
3 years ago
9

A scuba diver is using scuba gear to breathe under water. The pressure on her lungs is 2.5 atm and her lung volume is 4.4 L. Wha

t will happen to the volume of her lungs when the pressure increases to 4.5 atm?​
Chemistry
1 answer:
nikdorinn [45]3 years ago
3 0

Answer:

<h2>2.44 L</h2>

Explanation:

The volume can be used by using the formula for Boyle's law which is

P_1V_1 = P_2V_2 \\

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the final volume

V_2 =  \frac{P_1V_1}{P_2}  \\

We have

V_2 =  \frac{2.5 \times 4.4}{4.5}  =  \frac{11}{4.5}  \\  = 2.444444....

We have the final answer as

<h3>2.44 L</h3>

Hope this helps you

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What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom
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Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains 6.022\times 10^{23} atoms

So, 5.5 g of lead contains \frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22} atoms

and,

As, 118.71 g of lead contains 6.022\times 10^{23} atoms

So, 94.5 g of lead contains \frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23} atoms

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\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%

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\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

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