Br2 5mol take a 10 mol Br atoms mol
Answer:
1. Answer: The bowling ball has more potential energy as it sits on top of the building. It does not have any kinetic energy because it is not moving.
2. Answer: The bowling ball has equal amounts of potential and kinetic energy half way through the fall. At the half way point, half of the potential energy has been converted to kinetic energy.
3. Answer: Just before the ball hits the ground, it has more kinetic energy. As it hits the ground the potential energy becomes zero.
4. Answer:
PE=784 J
5. Answer:
PE = 392 J
6. Answer:
KE= 392 J
Also, since the PE and KE are equal at the half way point and PE =392 J, KE = 392 J.
7. What is the kinetic energy of the ball just before it hits the ground?
Answer:
KE=784 J
At first I answered in the comments, but I am able to answer now. I hope this can help
Answer:
<h2>12.38 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
m is the mass
v is the volume
From the question
m = 149.8 g
v = 12.1 mL
We have
We have the final answer as
<h3>12.38 g/mL</h3>
Hope this helps you
Answer: Volume occupied by given neon sample at standard condition is 123.84 L.
Explanation:
Given: 
= 105 L, 
, 
= 985 torr
At standard conditions,
= 273 K, 
= 760 K, 
= ?
Formula used to calculate the volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that volume occupied by given neon sample at standard condition is 123.84 L.
Answer:
// Program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program Starts here
#include<iostream>
using namespace std;
int main ()
{
// Declare Variables
int quarter, dimes, nickel, cent;
// Enter values for each
cout<<"Quarter: ";
cin>>quarter;
cout<<"Dimes: ";
cin>>dimes;
cout<<"Nickels: ";
cin>>nickel;
/*
In the United States, these coins have the following values
Quarter = 25 cents
Done = 10 cents
Nickel = 5 cent
Total cent is calculated below
*/
cent = 25 * quarter + 10 * dimes + 5 * nickel;
// Print Total
cout<<"The coins are worth "<<cent<<" cents";
return 0;
}
