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4 years ago

How will heat flow between objects?

2 answers:

5 0

Without an external agent doing work,heat will always flow from a hotter to a cooler object. Two objects of different temperature always interact. There arethree different ways for heat to flowfrom one object to another. They areconduction, convection, and radiation

How hope this helps❤

Pachacha [2.7K]4 years ago

3 0

Question: How will heat flow between objects?

from the colder object to the warmer object

from the bottom object to the object on top

from the warmer object to the colder object

back and forth between objects of equal temperature

Answer: Without an external agent doing work, heat will always flow from a hotter to a cooler object. Two objects of different temperature always interact. There are three different ways for heat to flow from one object to another. They are conduction, convection, and radiation.

Conduction: The process by which heat or electricity is directly transmitted through a substance when there is a difference of temperature or of electrical potential between adjoining regions, without movement of the material.

Convection: The movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat.

Radiation: The emission of energy as electromagnetic waves or as moving subatomic particles, especially high-energy particles that cause ionization.

Hope this helps, have a good day. c;

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bija089 [108]

Answer:

(B) 39

Explanation:

Use synthetic division:

-2 | 3 0 -1 3 1

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3 -6 11 -19 | 39

This means that the remainder is 39

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3 years ago

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A capacitor is being charged from a battery and through a resistor of 10 kΩ. It is observed that the voltage on the capacitor ri

swat32

Answer:

$C = 2.48 \times 10^{-4} Farad$

Explanation:

As per the equation of voltage on capacitor we know that

$V = V_{max}(1 - e^{-\frac{t}{\tau}})$

now we know that voltage reached to its 80% of maximum value in 4 second time

so we will have

$0.80 V_{max} = V_{max}(1 - e^{-\frac{4}{\tau}})$

$0.20 = e^{-\frac{4}{\tau}}$

$-\frac{4}{\tau} = ln(0.20)$

$-\frac{4}{\tau} = -1.61$

$\tau = 2.48$

as we know that

$\tau = RC$

$(10 k ohm)(C) = 2.48$

$C = 2.48 \times 10^{-4} Farad$

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3 years ago

There are two types of body waves that travel out of the epicenter Of an earthquake They have unique characteristic choose each

vova2212 [387]

Answer:

B. Fastest of the two waves

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Flash card name - Earth/Space Science Unit 1

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3 years ago

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The tub of a washer goes into its spin cycle, starting from rest and gaining angular speed steadily for 7.00 s, at which time it

Schach [20]

Answer:

The tub of the washer does 37.5 revolutions while it is in motion.

Explanation:

At first we assume that the tub accelerates and decelerates uniformly. In this case, it is required to determine the number of revolutions done by the tub by means of the following equations of motion:

Acceleration

$\ddot n_{1} = \frac{\dot n_{1}-\dot n_{1,o}}{t_{1}}$ (Eq. 1)

Where:

$\ddot n_{1}$ - Angular acceleration experimented by the tub, measured in revolutions per square second.

$\dot n_{1,o}$ , $\dot n_{1}$ - Initial and final angular velocities of the tub, measured in revolutions per second.

$t_{1}$ - Acceleration time, measured in seconds.

$\Delta n_{1} = \dot n_{1,o}\cdot t_{1}+\frac{1}{2}\cdot \ddot n_{1}\cdot t_{1}^{2}$ (Eq. 2)

Where $\Delta n_{1}$ is the change in angular position of the tub during acceleration, measured in revolutions.

Deceleration

$\ddot n_{2} = \frac{\dot n_{2}-\dot n_{1}}{t_{2}}$ (Eq. 3)

Where:

$\ddot n_{2}$ - Angular acceleration experimented by the tub, measured in revolutions per square second.

$\dot n_{1}$ , $\dot n_{2}$ - Initial and final angular velocities of the tub, measured in revolutions per second.

$t_{2}$ - Deceleration time, measured in seconds.

$\Delta n_{2} = \dot n_{1}\cdot t_{2}+\frac{1}{2}\cdot \ddot n_{2}\cdot t_{2}^{2}$ (Eq. 4)

If we know that $\dot n_{1,o} =0\,\frac{rev}{s}$ , $\dot n_{1} = 5\,\frac{rev}{s}$ , $t_{1} = 7\,s$ , $\dot n_{2} = 0\,\frac{rev}{s}$ and $t_{2} = 8\,s$ , then the amount of revolutions done by the tub during each phase is, respectively: