1) Potential energy before the fall: 98 J
The gravitational potential energy of an object is given by:
where m is the mass of the object, g is the gravitational acceleration and h the heigth of the object above the ground.
In this problem, m = 2 kg, g = 9.8 m/s^2 and h = 5 m: substituting into the equation, we find
2) Work done by gravity: 98 J
The work done by a force is given by:
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and the displacement
In this problem:
d = 5 m
Therefore,
Find the v first by using 3.14x0.22x2.16 div. 41g
Answer:
Number of Significant Figures: 3
The Significant Figures are 3 0 5
This is because the three zeros are considered trailing zeros because they're not between two numbers or after. Zeros attached to the beginning of a number in this way are called leading zeros. In decimals, this idea of zeros that don't add value to a number can be extended to trailing zeros. A trailing zero is any zero that appears to the right of both the decimal point and every digit other than zero.
Explanation:
Trailing zeros (zeros after non-zero numbers) in a number without a decimal are generally not significant (see below for more details). For example, 400 has only one significant figure (4). The trailing zeros do not count as significant. Trailing zeros in a number containing a decimal point are significant.
B. the mass of the building attracts you upward slightly
distance d = 5 km = 5 x 1000 m = 5000 m
time taken = 25 minute = 25 x 60 sec = 1500 sec
average velocity V = d/t
V = 5000/1500
V = 3.33 m/s towards east
