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vitfil [10]
3 years ago
11

What process is used to release energy in nuclear power plants

Physics
2 answers:
Hunter-Best [27]3 years ago
6 0
Fission is the process used to release energy in nuclear power plants (:
Anika [276]3 years ago
5 0
.........Nucler fission.... .
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3. What do we call the ONLY part of the electromagnetic spectrum that we can
otez555 [7]

Answer:

Visible Light

wavelength = 4000 - 7000 Angstroms = 400 - 700 milli-microns

1 A unit =  10^-10 m

1 mμ = 10^-9 m

6 0
2 years ago
The Escape speed at the surface of a certain planet is twice that of the earth. what is its mass in unit of earth's mass?
VLD [36.1K]

Answer:

22Km/sec

Explanation:

6 0
2 years ago
An object moving at a constant speed of 25 m/s is making a turn with a radius of curvature of 7 m (this is the radius of the "ki
prisoha [69]

Answer:

- 278.34 kg m/s^2

Explanation:

The rate of the change of momentum is the same as the force.

The force that an object feels when moviming in a circular motion is given by:

F = -mrω^2

Where ω is the angular speed and r is the radius of the circumference

Aditionally, the tangential velocity of the body is given as:

v = rω

The question tells us that

v = 25 m/s

r = 7m

mv = 78 kg m/s

Therefore:

m = (78 kg m/s) / (25 m/s) = 3.12 kg

ω = (25 m/s) / (7 m) = 3.57 (1/s)

Now, we can calculate the force or rate of change of momentum:

F = - (3.12 kg) (7 m)(3.57 (1/s))^2

F = - 278.34 kg m/s^2

4 0
3 years ago
Examples of buoyancy
Lana71 [14]
A ball would be something that floats in warter                                                                                                                                                            
5 0
3 years ago
If the car’s speed decreases at a constant rate from 60 mi/hmi/h to 50 mi/hmi/h in 3.0 ss, what is the magnitude of its accelera
Kitty [74]

Answer:

The magnitude of the acceleration is 1.2 × 10⁴ mi/h²

Explanation:

Hi there!

The acceleration is defined as the change in velocity in a time:

a = Δv / Δt

Where:

a = acceleration.

Δv = change in velocity  = final velocity - initial velocity.

Δt = elapsed time.

In this case:

Initial velocity = 60 mi/h

final velocity = 50 mi/h

elapsed time = 3.0 s

Let´s convert the time unit into h:

3.0 s · 1 h /3600 s = 1/1200 h

Now, let´s calculate the acceleration:

a = Δv / Δt

a = (50 mi/h - 60 mi/h) / 1/1200 h

a = -1.2 × 10⁴ mi/h²

The magnitude of the acceleration is 1.2 × 10⁴ mi/h²

7 0
3 years ago
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