1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
prohojiy [21]
3 years ago
12

A point charge q1=2.0μC is located on the positive y axis at y=0.30m, and an identical charge q2 is at the origin. Find the magn

itude and direction of the total force that these two charges exert on a third charge q3=4.0μC that is on the positive x axis at x=0.40m..A)In the same example, what is the magnitude of the net force on q3 if q1=2.0μC, as in the example, but q2=−2.0μC?B)In the same example, what is the direction of the force on q3 if q1=2.0μC, as in the example, but q2=−2.0μC?

Physics
2 answers:
weqwewe [10]3 years ago
8 0

Answer:

q1=2*10^-6 C

location is on positive y-axis at y=0.30 m

origin q2=0

q3=4*10^-3

x=0.40 m

F=q1*q2/r^2

The magnitude of force will be 98.97 N

And it will be in the negative y direction.

dalvyx [7]3 years ago
4 0

Answer:

(A) 0.279N at angle 38.02°

(B) 0.701N

(C) 14.19°

Explanation:

(A) The net force on q3 is given as:

F = Fxi + Fyj

Fx is the x component of the force

Fy is the y component of the force

Fx = -F(1, 3)cos(90 - x) + F(2, 3)cos0

Fy = -F(2, 3)cosx - F(2, 3)cos90 = -F(2, 3)cosx

First let us find y and angle x from the diagram.

Using Pythagoras theorem,

y² = 0.3² + 0.4²

y² = 0.25

y = 0.5m

Using SOHCAHTOA to find x,

sinx = 0.4/0.5

x = 53.13°

Electrostatic force, F is given as:

F = kqQ/r²

Where k = Coulumbs constant

F(1,3) = (k*q1*q3) / r²

F(1, 3) = (9 * 10^9 * 2.0 * 10^(-6) * 4.0 * 10^(-6)) / (0.5²)

F(1, 3) = 0.288N

F(2,3) = (k*q2*q3) / r²

F(2, 3) = (9 * 10^9 * 2.0 * 10^(-6) * 4.0 * 10^(-6)) / (0.4²)

F(2, 3) = 0.45N

Therefore,

Fx = -0.288cos36.87 + 0.45

Fx = 0.22N

Fy = 0.288cos53.13

Fy = 0.172N

=> F = 0.22i + 0.172j

The magnitude of the force will be

F(mag) = √(0.22² + 0.172²)

F(mag) = 0.279N

The direction of the force makes will be

tanθ = Fy/Fx

tanθ = 0.172/0.22 = 0.781

θ = 38.02° to the x axis.

(B) q2 = - 2.0 * 10^(-6)

This implies that:

F(2,3) = (k*q2*q3) / r²

F(2, 3) = (9 * 10^9 * -2.0 * 10^(-6) * 4.0 * 10^(-6)) / (0.4²)

F(2, 3) = -0.45N

Therefore,

Fx = -0.288cos36.87 - 0.45

Fx = -0.68N

Fy = 0.172N

=> F = - 0.68i + 0.172j

The magnitude of the force will be

F(mag) = √((-0.68)² + 0.172²)

F(mag) = 0.701N

(C) The direction of the force makes will be

tanθ = 0.172/0.68

θ = 14.19° to the x axis

You might be interested in
What are three examples of constructive forces
Olin [163]
The three main constructive forces are crustal deformation, volcanic eruptions, and deposition of sediment.
5 0
3 years ago
Suppose the student in (Figure 1) is 68kg, and the board being stood on has a 12kg mass. What is the reading on the left scale?
lesantik [10]

The equilibrium conditions allow to find the results for the balance forces are:

  • F₁ = 225.4 N
  • F₂ = 558.6 N

When the acceleration is zero we have the equilibrium conditions for both linear and rotational motion.

            ∑ F = 0

            ∑ τ = 0

           

Where F are the forces and τ the torques.

The torque  is the product of the force and the perpendicular distance to the point of support,

The free-body diagrams are diagrams of the forces without the details of the bodies, see attached for the free-body diagram of the system.

We write the translational equilibrium condition.

           F₁ - W₁ - W₂ + F₂ = 0

We write the equation for the rotational motion, set our point of origin at scale 1, and the counterclockwise turns are positive.

         F₂ 2 - W₁ 1 - W₂ 1.5 = 0\frac{W_1  \ 1 + W_2 \ 1.5}{2}

Let's calculate F₂

         F₂ = \frac{W_1 \ 1 + W_2 \ 1.5 }{2}  

         F₂ = (m g + M g 1.5)/ 2

         F₂ = \frac{(12 + 68 \ 1.5 ) \  9.8}{2}  

         F₂ = 558.6 N

We substitute in the translational equilibrium equation.

         F₁ = W₁ + W₂ - F₂

         F₁ = (m + M) g - F₂

         F₁ = (12 +68) 9.8 - 558.6

         F₁ = 225.4 N

In conclusion using the equilibrium conditions we can find the forces of the balance are:

  • F₁ = 225.4 N
  • F2 = 558.6 N

Learn more here:  brainly.com/question/12830892

5 0
2 years ago
In an experiment, a variable, position-dependent force FC) is exerted on a block of mass 1.0 kg that is moving on a horizontal s
marshall27 [118]

Answer:

C) The function F(x) for 0 < x < 5, the block's initial velocity, and the value of Fr.

Explanation:

Yo want to prove the following equation:

W_N=\Delta K\\\\

That is, the net force exerted on an object is equal to the change in the kinetic energy of the object.

The previous equation is also equal to:

F(x)x-F_f=\frac{1}{2}m(v_f^2-v_o^2)    (1)

m: mass of the block

vf: final velocity

v_o: initial velocity

Ff: friction force

F(x): Force

x: distance

You know the values of vf, m and x.

In order to prove the equation (1) it is necessary that you have C The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F.  Thus you can calculate experimentally both sides of the equation.

8 0
3 years ago
A circular loop ( radius = 0.5 m) carries a current of 3.0 A and has unit normal vector of (2i - j +2k)/3 what is x component of
Roman55 [17]

Answer:

T=9.42Nm

Explanation:

From the question we are told that:

Radius r= 0.5 m

Current I= 3.0 A

Normal vector n=\frac{(2i - j +2k)}{3}

Magnetic field B= (2i-6j) T

Generally the equation for Area is mathematically given by

 A=\pi r^2

 A=3.1415 *0.5^2

 A=0.7853 m^2

Generally the equation for Torque is mathematically given by

 T=A(i'*B)

Where

 i'*B= \begin{bmatrix}2&-1&2\\2&-6&0\end{bmatrix}

 X\ component\ of\ i'*B= [(-1 * 0)-(2*-6)]

 X\ component\ of\ i'*B=12

Therefore

 T=0.7853*12

 T=9.42Nm

7 0
2 years ago
Sodium and potassium are positively charged ions called cations, and chloride and phosphate form negatively charged ions called
Alecsey [184]
 Sodium and potassium are positively charged ions called cations, and chloride and phosphate form negatively charged ions called anions. is true!

7 0
3 years ago
Other questions:
  • Answer for brainliest and mad points pllllssssssss
    7·1 answer
  • Two boys are standing on a bridge 10 m above a stream. One boy throws a rock horizontally with speed of 5.0 m/s at exactly the s
    8·1 answer
  • a. Of the three experiments that are used to confirm the Big Bang theory, which is the most interesting to you and why?
    7·1 answer
  • Calculate the mass of sodium thiosulfate pentahydrate needed to prepare 500 ml of an approximately 0.10 m solution
    8·1 answer
  • Explain what happens when a ferromagnetic material is made into a permanent magnet.
    8·1 answer
  • A thin aluminum meter stick hangs from a string attached to the 50.0 cm mark of the stick. From the 0.00 cm mark on the meter st
    9·1 answer
  • gabriel and arely have performed an experiment and are not sure their results are valid. what should they do to check their resu
    11·2 answers
  • Taylor Swift weighing 794 N gets on an elevator. The elevator uses 313 W of power to lift the person 22.0 m. How much time did t
    5·1 answer
  • Help ME please, I'M BENG TIMED
    5·1 answer
  • In Case 1, a mass M hangs from a vertical spring having spring constant k and is at rest in its equilibrium position. In Case 2
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!