Answer:
i THINK it’s false. You don’t have to give me points ;-;
Explanation:
Answer:
-4.8 m/s²
Explanation:
Apply Newton's second law:
∑F = ma
F − mg = ma
300 N − (60 kg) (9.8 m/s) = (60 kg) a
a = -4.8 m/s²
The acceleration five seconds after jumping is 4.8 m/s² downward.
Check the 1st 2nd 3rd and 4th boxes
Answer:
<em>The speed of the passengers is 5.24 m/s</em>
Explanation:
<u>Uniform Circular Motion
</u>
It occurs when an object in a circular path travels equal angles in equal times.
The angular speed can be calculated in two different ways:
![\displaystyle \omega=\frac{v}{r}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Comega%3D%5Cfrac%7Bv%7D%7Br%7D)
Where:
v = tangential speed
r = radius of the circle described by the rotating object
Also:
![\omega=2\pi f](https://tex.z-dn.net/?f=%5Comega%3D2%5Cpi%20f)
Where:
f = frequency
Since the frequency is calculated when the number of revolutions n and the time t are known:
![\displaystyle f=\frac{n}{t}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%3D%5Cfrac%7Bn%7D%7Bt%7D)
The Ferris wheel has a diameter of 100 m and makes n=1 rotation in t=60 seconds, thus the frequency is:
![\displaystyle f=\frac{1}{60}\ Hz](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%3D%5Cfrac%7B1%7D%7B60%7D%5C%20Hz)
The angular speed is:
![\displaystyle \omega=2\pi \frac{1}{60} =\frac{\pi}{30} \ rad/s](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Comega%3D2%5Cpi%20%5Cfrac%7B1%7D%7B60%7D%20%3D%5Cfrac%7B%5Cpi%7D%7B30%7D%20%5C%20rad%2Fs)
Now we calculate the tangential speed, solving this formula for v:
![\displaystyle \omega=\frac{v}{r}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Comega%3D%5Cfrac%7Bv%7D%7Br%7D)
![v=\omega . r](https://tex.z-dn.net/?f=v%3D%5Comega%20.%20r)
The radius is half the diameter, r=100/2=50 m:
![\displaystyle v=\frac{\pi}{30} . 50](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%3D%5Cfrac%7B%5Cpi%7D%7B30%7D%20.%2050)
Calculating:
v = 5.24 m/s
The speed of the passengers is 5.24 m/s