Answer:
(C) P = 7.4 torr, because it is directly proportional to the initial pressure of HI.
Explanation:
From the equation of reaction,
Kc = [H2][I2]/[HI]^2
Kc = 0.0016
Initial pressure of HI = 200 torr
Let the equilibrium pressure of I2 be y
Mole ratio of H2 to I2 from the equation of reaction is 1:1, equilibrium pressure of H2 is also y
Mole ratio of HI to I2 is 2:1, equilibrium pressure of HI is (200 - 2y)
0.0016 = y×y/(200 - 2y)^2
y^2 = 0.0016(40,000 - 800y + 4y^2)
y^2 = 64 - 1.28y + 0.0064y^2
y^2 - 0.0064y^2 + 1.28y - 64 = 0
0.9936y^2 + 1.28y - 64 = 0
y^2 + 1.29y - 64.41 = 0
The value of y must be positive and is obtained by the use of the quadratic formula.
y = [-1.29 + sqrt(1.29^2 - 4×1×-64.41)] ÷ 2(1) = [-1.29 + 16.10] ÷ 2 = 14.81 ÷ 2 = 7.4
Equilibrium pressure of I2 is 7.4 torr because the relationship between I2 and HI is direct in which increase in one quantity (initial pressure of HI) would result to a corresponding increase in the other quantity (equilibrium pressure of I2)
Theoretical
yield is the amount supposedly produced by the reaction if it was complete. The
balanced chemical reaction is:<span>
</span>
<span> C2H6 + Cl2 = C2H5Cl + HCl</span>
<span>
We use the amounts given for the reactants as
the starting point of the calculations to determine the limiting reactant. We do as follows:
150 g C2H6 ( 1 mol / 30.08 g
) = 4.987 mol
205 g Cl2 ( 1 mol / 70.9 g ) = 2.891 mol
Therefore, the limiting reactant would be Cl2 since it would be consumed completely first in the reaction.
We use this for the theoretical yield.
<span>2.891 mol Cl2 ( 1 mol C2H5Cl / 1 mol Cl2 ) = </span>2.891 mol C2H5Cl (THEORETICAL YIELD)
172 g ( 1 mol / 64.52 g ) = 2.666 mol C2H5Cl (
ACTUAL YIELD)
Percent yield = 2.666 / 2.891 x 100 = 92.21%</span>
Answer:
Please see the attached picture.
Explanation:
Magnesium chloride involves a metal and a non-metal so it is an ionic bonding. (Involves transfer of electrons not sharing)
① Write down the electronic configuration of magnesium and chlorine.
✓ You have written it down correctly :)
② Write down the charges of the magnesium and chlorine ion. You can do this with the help of the periodic table. Since magnesium is in group 2, its charge is 2+ and since chlorine is in group 7, its charge is -1.
For better understanding, what we are trying to achieve here is a stable octet or duplet structure. To do this, the atoms have to gain or lose electrons. For magnesium, it could either lose 2 electrons or gain 6 electrons to ensure that there is 8 valence electrons. But it is easier to lose 2 electrons (takes lesser energy) thus the charge is +2. (To remember better, magnesium gives away 2 electrons so it is a "positive act" and hence its charge is positive 2. Don't take that literally though ^^)
③ Write down the formula of the compound and that will help you know how many atoms of each element are involved. (MgCl₂ ➪ 1 Mg atom and 2 Cl atoms)
④ Draw the dot and cross diagram.
☆ Since the 2 electrons in the 3rd shell of magnesium atom have been given away, the last shell is empty so there is only 2 shells left. ( Draw 2 circles only)
Chlorine atom gains another electron hence the 2nd shell becomes full (stable) and thus, you still have to draw 2 circles.
•It is encouraged to include the key to explain your symbols such as the dots and crosses.
Answer:
Potential energy for n = 6 Bohr orbit electron is -1.21*10⁻¹⁹J
Explanation:
As per the Bohr model, the potential energy of electron in an nth orbit is given as:
here:
k = Coulomb's constant = 9*10⁹ Nm2/C2
Z = nuclear charge
e = electron charge = 1.6*10⁻¹⁹ C
r(n) = radius of the nth orbit = n²(5.29*10⁻¹¹m)
Substituting for k, Z(= 1), e and r(n) in the above equation gives:
No , it’s a carboxylic Easter