Answer:
Percentage yield = 57.57%
Explanation:
Given data:
Actual yield of carbondioxide = 38.0 g
Mass of propane = 22.05 g
Percentage yield = ?
Solution:
Chemical equation:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Number of moles of propane:
Number of moles of propane = mass / molar mass
Number of moles of propane = 22.05 g/ 44 g/mol
Number of moles of propane = 0.5 mol
Now we compare the moles of carbon dioxide with moles of propane.
C₃H₈ : CO₂
1 : 3
0.5 : 3×0.5 = 1.5 mol
Mass of carbondioxide:
Mass of carbondioxide = moles × molar mass
Mass of carbondioxide = 1.5 mol × 44 g/mol
Mass of carbondioxide = 66 g
Percentage yield:
Percentage yield = actual yield / theoretical yield × 100
Percentage yield = 38 g/ 66 g × 100
Percentage yield = 57.57%
