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4 years ago

The atmospheric gas that forms a mild acid when dissolved in water is ____

Chemistry

2 answers:

mario62 [17]4 years ago

6 0

What do you think it is? I'll give you a hint, it's either A or C. Don't guess, just try.

Alchen [17]4 years ago

3 0

The correct answer that would best complete the given statement above would be the first option: CARBON DIOXIDE. <span>The atmospheric gas that forms a mild acid when dissolved in water is carbon dioxide. Hope this is the answer that you are looking for. </span>

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Question 28 (2 points)

Afina-wow [57]

Answer:

Il of the above are part of the Kinetic Molecular Theory

Explanation:

4 0

3 years ago

A reaction of importance in the formation of smog is that between ozone and nitrogen monoxide described by O3(g)+NO(g)⟶O2(g)+NO2

julsineya [31]

Answer:

Initial rate of reaction is $2.07\times 10^{-3}M.s^{-1}$ .

Explanation:

It is a second order reaction.

Initial rate of reaction = $k[O_{3}]_{0}[NO]_{0}$ , where k is rate constant, $[O_{3}]_{0}$ is the initial concentration of $O_{3}$ and $[NO]_{0}$ is the initial concentration of NO.

Here, k = $4.09\times 10^{6}M^{-1}.s^{-1}$ , $[O_{3}]_{0}=5.84\times 10^{-6}M$ and $[NO]_{0}=8.65\times 10^{-5}M$

So, initial rate of reaction = $(4.09\times 10^{6}M^{-1}.s^{-1})\times (5.84\times 10^{-6}M)\times (8.65\times 10^{-5}M)$

= $2.07\times 10^{-3}M.s^{-1}$

So, initial rate of reaction is $2.07\times 10^{-3}M.s^{-1}$

8 0

3 years ago

Calculate the mass of hydrogen formed when 27 g of aluminum reacts with excess hydrochloric acid according to the balanced equat

Alex

6.069 grams is the mass of hydrogen formed when 27 g of aluminum reacts with excess hydrochloric acid.

Explanation:

Balanced equation for the reaction:

2 Al + 6 HCl → 2 AlCl₃ + 3 H₂

data given:

mass of aluminum = 27 grams

atomic mass of one mole of aluminum = 26.89 grams/mole

formula to calculate number of moles:

number of moles = $\frac{mass}{atomic mass of one mole}$

number of moles = $\frac{27}{26.89}$

= 1.004 moles of aluminum will react

from the balanced equation:

2 moles of Al reacted to form 3 moles of H2

1.004 moles of Al will produce x moles of H2

$\frac{3}{2}$ = $\frac{x}{1.004}$

x = 3.012 moles of H2 will be formed.

mass will be calculated as number of moles multiplied by atomic weight

mass of 3.012 moles of hydrogen ?(atomic weight of one mole H2 = 2.015 grams)

= 3.012 x 2.015

= 6.069 grams of H2 will be formed.

6 0

3 years ago

An electron in an atom is known to be in a state with magnetic quantum number ml=0. What is the smallest possible value of the p

rusak2 [61]

Answer:

Explanation:

The principal quantum number, n, showsthe principal electron shell. which can inturn be describe as the most probable distance of the electrons from the nucleus, the larger the number n is, the farther the electron is from the nucleus, the larger the size of the orbital, and the larger the atom is. n can be any positive integer starting at 1, as n=1 designates the first principal shell (the innermost shell). When an electron is in an excited state or it gains energy, it may jump to the second principle shell, where n=2

As the energy of the electron increases, so does the principal quantum number, e.g., n = 3 indicates the third principal shell, n = 4 indicates the fourth principal shell, and so on. n=1,2,3,4…

On the other hand, the magnetic quantum number ml determines the number of orbitals and their orientation within a subshell. Consequently, its value depends on the orbital angular momentum quantum number l. Given a certain l, ml is an interval ranging from –l to +l, so it can be zero, a negative integer, or a positive integer. ml=−l,(−l+1),(−l+2),…,−2,−1,0,1,2,…(l–1),(l–2),+l

note also that: The orbital angular momentum quantum number l determines the shape of an orbital, and therefore the angular distribution. The number of angular nodes is equal to the value of the angular momentum quantum number l. Each value of l indicates a specific s, p, d, f subshell (each unique in shape.) The value of l is dependent on the principal quantum number n. Unlike n, the value of l can be zero. It can also be a positive integer, but it cannot be larger than one less than the principal quantum number (n-1): l=0,1,2,3,4…,(n−1).

So the answer is 1

3 0

4 years ago

:answer question number 10

Vesna [10]

Answer:

the last one

Explanation:

I'm pretty sure

8 0

3 years ago

Read 2 more answers