Answer:
13.896 kg
Step-by-step explanation:
You can find the mass of the bar by first finding the volume.
V = BH
where B = area of the base (the trapezium), and
H = height (distance trapezium between bases)
The area of a trapezium is
A = (b1 + b2)h/2
where b1 and b2 are the lengths of the bases of the trapezium (the parallel sides), and
h = the altitude of the trapezium (distance between the bases of the trapezium)
V = (b1 + b2)h/2 * H
V = (12 cm + 6 cm)(5 cm)/2 * 16 cm
V = 720 cm^3
The volume of the bar is 720 cm^3.
Now we use the density and the volume to find the mass.
density = mass/volume
mass = density * volume
mass = 19.3 g/cm^3 * 720 cm^3
mass = 13,896 g
Now we convert grams into kilograms.
1 kg = 1000 g
mass = 13,896 g * (1 kg)/(1000 g)
mass = 13.896 kg
Answer: 1.3896 kg
2/3 is .666666 so that would be the percent
<span>Area of circular metal=πr^2
=3.14 x 3.5 x 3.5 m^2
now,
total cost=area x rate
=3.14 x 3.5 x 3.5 x 3.25 $
=125.01 $</span>
[ Answer ]
[ Explanation ]
Area = 1420
Width = 
Area For Rectangle: Length · Width
Use division to find width:
1420 ÷
Convert mixed numbers to fractions:
1420 = 
= 
÷
Use mixed multiplication:
= 
Simplify:
= 
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