In order to find your answer you need to be <span>measuring entropy, so you will be using the following formula:
</span><span>delta S= S of (N2H4) + S of ( H2) - [2( S of NH3)]
</span>Hope this is very useful for you
Answer:
Iron(III) Chlorate Fe(ClO3)3 Molecular Weight
Explanation:
Answer:
0.48 moles
Explanation:
The bromide has a molarity of 2.6M.
This simply means that in 1dm^3 or 1000cm^3 of the solution, there are 2.6 moles.
Now, we need to get the number of moles in 185ml of the bromide. It is important to note that the measurement ml is the same as cm^3.
We calculate the number of moles as follows.
If 2.6mol is present in 1000ml
x mol will be present in 185 ml.
To calculate x = (185 * 2.6) ÷ 1000
= 0.481 moles = 0.48 moles to 2 s.f
Answer:
1.5 mol
Explanation:
Step 1: Given data
- Volume of argon gas: 33 L
- Standard temperature: 273.15 K
Step 2: Calculate the moles corresponding to 33 L of argon at standard temperature and pressure (STP)
At STP, 1 mole of argon gas occupies 22.4 L.
33 L × 1 mol/22.4 L = 1.5 mol
Answer:
30 moles of solute
Explanation:
15 M = moles/2 liters
moles = Molarity * Liters
moles = 15 M * 2 Liters
moles = 30
