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3 years ago

PLEASE HELP ME ON HERE HAVING TROUBLE!!!! What errors tend to lead to pseudoscience?

Chemistry

1 answer:

guajiro [1.7K]3 years ago

5 0

Answer:

Some errors includes:

- Having contradictory information

- Exaggerated and false cliams

- Reliance on bias rather than facts

- etc

Explanation:

Pseudoscience is a non-science that falsely portrays itself as real science. It does so by copying parts of real science or ignoring sections of the scientific method within an investigation. Even a tiny mistake can turn a scientific explanation into a pseudoscientific claim.

For example, if a group of scientists want to know if students prefer the taste of a particular type of soda, they must control all factors in their experiment except for the students' sense of taste. If they conduct their tests on students and allow them to see the color of the soda they are testing, then their results are unreliable. There is bias in their results. They would not be able to claim any preference for one soda or another because students may have picked a soda based on its color, not its taste.

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Magnesium (average atomic mass = 24.3050 amu) consists of three isotopes with masses 23.9850 amu, 24.9858 amu, and 25.9826 amu.

iris [78.8K]

Answer: The first isotope has a relative abundance of 79% and last isotope has a relative abundance of 11%

Explanation: Given that the average atomic mass(M) of magnesium

= 24.3050amu

Mass of first isotope (M1) = 23.9850amu

Mass of middle isotope (M2)=24.9858amu

Mass of last isotope(M3)= 25.9826amu

Total abundance = 1

Abundance of middle isotope = 0.10

Let abundance of first and last isotope be x and y respectively.

x+0.10+y =1

x = 0.90-y

M = M1 × % abundance of first isotope + M2 × % of middle isotope +M3 ×% of last isotope

24.03050= 23.985× x + 24.9858 ×0.10 + 25.9826×y

Substitute x= 0.90-y

Then

y = 0.11

Since y=0.11, then

x= 0.90-0.11

x=0.79

Therefore the relative abundance of the first isotope = 11% and the relative abundance of the last isotope = 79%

5 0

2 years ago

To what volume should you dilute 50.0 ml of 12 m hno3 solution to obtain a 0.100 m hno3 solution?

bearhunter [10]

Answer:

The answer is "6L"

Explanation:

Formula:

$\bold{C_1 \times V_1 = C_2 \times V_2 }\\\\V_2= \frac{C_1\times V_1}{C_2}$

Values:

$\to C_1= 12 \ m\\\to V_1= 50 \ ml\\\to C_2= 0.100 \ m\\\\\\V_2= \frac{12 \times 50 }{0.100}$

$= \frac{12 \times 50 }{0.100}\\\\= \frac{12 \times 50 \times 1000}{100}\\\\= \frac{600 \times 1000}{100}\\\\= 600 \times 10\\\\=6000 \ ml\\= 6 \ L$

4 0

3 years ago

Which law was used to determine the relationship between the volume and the number of moles?

lawyer [7]

Answer:

The Mole-Volume Relationship: Avogadro's Law. A plot of the effect of temperature on the volume of a gas at constant pressure shows that the volume of a gas is directly proportional to the number of moles of that gas. This is stated as Avogadro's law.

Explanation:

4 0

3 years ago

N2 + 3 H2 – 2 NH3 How many moles of nitrogen (N2) are required to get 6

Iteru [2.4K]

Answer:

N2 + 3H2 → 2NH3. 14 moles a. If 6 mol of H2 are consumed, how many moles of NH3 are produced? ... a 3 mol H₂. 4. How many moles of nitrogen are needed to make 11 moles of NH3? Il mol NH₃ x Imol Na = 15.5

5 0

3 years ago

How many liters are in 5.42 mols of O2 gas?<br><br> (2 decimal places)

Debora [2.8K]

Explanation:

1 mol = 22.4 l

5.42 mol = 22.4 × 5.42 = 121.408

in two decimal place it is 121.41

7 0

3 years ago