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loris [4]
3 years ago
6

1. What type of chemical reaction is the following equation? AIBr3 +K → KBr + AI

Chemistry
2 answers:
Annette [7]3 years ago
8 0

Answer:    Single Displacement (Substitution)

Explanation:

Aluminum Bromide + Potassium = Potassium Bromide + Aluminum

muminat3 years ago
6 0

Answer:

Explanation:

It is called a single replacement. K is one of the few chemicals that can force Aluminum to take on electrons. The balanced equation is

AIBr3 +3K → 3KBr + AI

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Which of these charges has the greatest magnitude
Natalka [10]

Answer:

magnitude means absolute value, so the one that is greastest, like |-7| and |4| even id |-7| is a negative number, but it is still the one farthest away from 0, so |-7| is greater than |4|.

That is the way to find the greatest magnitude, but because I don't know your numbers so I can not answer your question, but this is the way to solve for it.

HOPE THIS HELPS!!!!!!!!!( IF IT DOES <u><em>PLEASE MARK ME AS BRAINLIEST )</em></u>

6 0
3 years ago
Which number in a chemical formula tells you how many atoms of element you have
galina1969 [7]

Answer:it doesn’t

Explanation:

4 0
3 years ago
Read 2 more answers
If an object with a volume of 105 mL and a density of 0.801 g/mL, what is the objects mass?
garik1379 [7]

Answer:

The objects mass is 84, 105 g. See the explanation below, please.

Explanation:

We use the formula:

Density= mass/volume

Mass= Density x volume =0.801 g/mL x 105 mL = 84, 105 g

6 0
3 years ago
What pressure (in atm) will 0.44 moles of co2 exert in a 2.6 l container at 25°c?
Lilit [14]
We can use the ideal gas law equation to find the pressure 
PV = nRTwhere 
P - pressure 
V - volume  - 2.6 x 10⁻³ m³ 
n - number of moles - 0.44 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values into the equation,
P x 2.6 x 10⁻³ m³  = 0.44 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
P = 419 281.41 Pa
101 325 Pa is equivalent to 1 atm 
Therefore 419 281.41 Pa - 1/ 101 325 x 419 281.41 = 4.13 atm
Pressure is 4.13 atm
6 0
3 years ago
!!MARKING BRAINLIEST!! Please help this is due at midnight!! No websites please just help me! :(
9966 [12]

Answer:

I'll do the first one for you. The reason why I'm not going to do the rest is because this is pretty simple stuff. I'll explain how I got the answer, please read it ^^ the rest of the problems should be a breeze.

1. 5.454285714285714 liters, or approx. 5.45 liters

Explanation:

P1V2 = P2V2

P1 refers to the original pressure. V1 refers to the original volume, or the amount of space the gas takes up.

P2 and V2 refer to the final pressure or volume, accordingly.

You insert the values into the equation, like so:

(8.3)(46) = (70)(x)

Now, multiply.

381.8 = 70x

Use inverse operations to find the value of x. Divide 381.8 by 70 to isolate x.

381.8/70 = x

5.454285714285714 = x

The volume of the gas when the pressure is increased to 70.0 mm Hg is approximately 5.45 liters. Don't forget about the units at the end, when you write your final answer.

Important! When pressure <em>increases</em>, volume <em>decreases, </em>and vice versa. Volume and pressure for gases are <em>inversely proportional. </em>So even though the pressure increased, that doesn't mean the volume increases, too.

<em>You can check your answers easily!</em>

Just multiply your final answer by its corresponding pressure or volume and compare it to the other. I hope that made sense. Like so:

5.454285714285714 x 70 = 381.8

8.3 x 46 = 381.8

That makes P1V2 DOES equal P2V2, and your answer is correct.

I hope this helped in time for you to submit it before the deadline! Good luck.

<em>Tips! </em>

For #2: I'm pretty sure the mentioning of the temperature (25.0 °C) doesn't matter. You can ignore it, it won't affect your calculations.

For #4: the standard pressure in mm Hg (millimeters of mercury) is 760 mm Hg. That's your P2.

6 0
3 years ago
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