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Arturiano [62]
3 years ago
11

Which of the following statements is true? A) The iron atom is best considered to be a solid. B) The mercury atom is best consid

ered to be a liquid. C) The helium atom is best considered to be a gas. D) At least two of the above statements are correct. E) None of the above statements are correct.
Chemistry
2 answers:
ale4655 [162]3 years ago
8 0
The answer would be D.
shepuryov [24]3 years ago
3 0
I believe the correct response would be D. At least 2 of the above statements are correct.
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Answer:

6 is the right answer I know cause I like science

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3 years ago
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Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?
chubhunter [2.5K]

Answer:

8.625 grams of a 150 g sample of Thorium-234  would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample  to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now  we start with 150 grams  of Thorium-234

150 \times \frac{1}{2}=24.1

75 \times \frac{1}{2} =48.2

34.5 \times \frac{1}{2} =72.3

17.25 \times \frac{1}{2} =96.4

8.625\times \frac{1}{2} =120.5

So after 120.5 days the amount of sample that remains is 8.625g

In simpler way , we can use the below formula to find the sample left

A=A_{0} \cdot \frac{1}{2^{n}}

Where

A_0  is the initial sample amount  

n = the number of half-lives that pass in a given period of time.

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3 years ago
The forensic technician at a crime scene has just prepared a luminol stock solution by adding 13.0 g of luminol into a total vol
Andrews [41]

Answer:

0.978 M

Explanation:

Given data

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We can find the molarity of the stock solution of luminol using the following expression.

M = mass of solute / molar mass of solute × liters of solution

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For c2h3o2−, write an equation that shows how the anion acts as a base.
velikii [3]
The synthetic compound Zn(C2H3O2)2 is zinc acetic acid derivation. The molecular composition demonstrates that the mixes incorporate zinc, spoke to by Zn; carbon, spoke to by C; hydrogen, spoke to by H; and oxygen, spoke to by O. Below is the <span>an equation that shows how the anion acts as a base:

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C2H3O2−(aq)+H2O(l)⇌<span>HC2H3O2(aq)+OH−(aq)</span>

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