The molarity of Sr(OH)2 solution is = 0.1159 M
calculation
write the equation for reaction
that is, Sr(OH)2 +2HCl→ SrCl2 + 2 H2O
then finds the mole of HCl used
moles = molarity x volume
=40.03 x0.1159 = 4.639 moles
by use of mole ratio between Sr(OH)2 to HCL which is 1 :2 the moles of Sr(OH)2 is therefore = 4.639 x1/2 = 2.312 moles
molarity of Sr(OH)2 is = moles / volume
=2.312 /20 =0.1159 M
Answer: Molarity increases
Explanation:
Molarity, also known as concentration in moles/dm3 or g/dm3, is calculated by dividing the amount of solute dissolved by the volume of solvent. So, Molarity (c) = amount of solute (n) / volume (v)
i.e c = n/v
Hence, molarity is directly proportional to the amount of solute dissolved, and inversely proportional to the volume of solvent.
Thus, at same volume, any increase in solute amount increases molarity while a decrease will also decreases molarity.
Yo sup??
we can solve this problem by applying Newton's 2nd law
F*t=Δp
p=momentum
pi=mu=1500*30
pf=mv=m*0=0
Therefore
F*3=1500*30
F=15000 N
Hope this helps.
I think it’s A. The force of the stirring
The amount of water that could we get if you started with 250.0 grams of hydrogen is 2,250 grams.
<h3>What is moles - mass realation?</h3>
Moles (n) and mass of any substance are related to each other according to the given equation as:
n = W/M, where
W = given mass
M = molar mass
Given balanced chemical reaction is:
2H₂ + O₂ → 2H₂O
Moles of 250g of H₂ = 250g / 2g/mol = 125mol
From the stoichiometry of the reaction it is clear that,
2 moles of H₂ = produces 2 moles of H₂O
125 moles of H₂ = produces 125 moles of H₂O
Now mass of water will be calculated as:
Mass = (125mol)(18g/mol) = 2,250g
Hence required mass of water is 2,250 grams.
To know more about moles & mass, visit the below link:
brainly.com/question/24631381
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