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Misha Larkins [42]

3 years ago

14

an elastic material of length 3m is to be stretched to produce an extension three times it's original length. Calculate the forc

e required to produce the extension if the force constant of the material is 982.3 Newton per metre

1 answer:

Anastaziya [24]3 years ago

7 0

Answer:

F = 8840.7 N

Explanation:

The parameters given are:

Length L = 3 metres

Extension e = 3 × 3 = 9m

Force constant K = 982.3 Newton per metre

From Hook's law,

Provided the elastic limit is not extended, the extension is directly proportional to the force applied.

That is,

F = Ke

Substitute all the parameters into the formula

F = 982.3 × 9

F = 8840.7 N

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(See explanation for further information)

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Venus - $67.240\times 10^{6}\,mi$

Earth - $92.960\times 10^{6}\,mi$

Mars - $141.600\times 10^{6}\,mi$

Jupiter - $483.800\times 10^{6}\,mi$

Saturn - $888.200\times 10^{6}\,mi$

Uranus - $1,787\times 10^{6}\,mi$

Neptune - $2,795\times 10^{6}\,mi$

b) The solutions are presented below:

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$\Delta s = 416.560\times 10^{6}\,mi$

B. The combined distance from the Sun is:

$\Delta s = 57.909\times 10^{6}\,mi + 67.240\times 10^{6}\,mi +92.960\times 10^{6}\,mi$

$\Delta s = 218.109\times 10^{6}\,mi$

Which is less than the distance from the Sun to Neptune ( $2,795\times 10^{6}\,mi$ ).

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Scientific notation:

$\Delta s = 929.600\times 10^{6}\,mi-888.200\,\times 10^{6}\,mi$

$\Delta s = 41.4\times 10^{6}\,mi$

Standard notation:

$\Delta s = 929,600,000\,mi - 888,200,000\,mi$

$\Delta s = 41,400.000\,mi$

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