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dangina [55]
3 years ago
10

Sketch a position-time graph for a bear starting

Physics
1 answer:
Dmitrij [34]3 years ago
3 0

Explanation:

hopefully that makes sense. the position doesn't change over the 5 seconds, meaning it's stopped but time still continues. then when the slope is negative this shows the bear's position becoming negative (backing up, changing direction).

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(a) Find the position vector of a particle that has the given acceleration and the specified initial velocity and position. a(t)
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Answer:

r(t)=(\frac{10t^3}{3}+t)i+(-sint+t+1)j+(\frac{-cos2t}{4}+\frac{1}{4})k

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given v(0)=i

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from equation 1

V(t)=(10t^2+c_1)i+(-cost+c_2)j+\frac{sin2t}{2}k----------eqn 2

now r(t)=\int\limits^a_b {v (t)} \, dt

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given r(0)=j

0i+1j+ok = c_1i+c_2j+(\frac{-1}{4}+c_3)k

c_1=0  c_2=0  c_3 =  \frac{1}{4}

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