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dangina [55]
3 years ago
10

Sketch a position-time graph for a bear starting

Physics
1 answer:
Dmitrij [34]3 years ago
3 0

Explanation:

hopefully that makes sense. the position doesn't change over the 5 seconds, meaning it's stopped but time still continues. then when the slope is negative this shows the bear's position becoming negative (backing up, changing direction).

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Which change would decrease the total current, I, flowing through this circuit?
iren [92.7K]

Answer:

A. Increasing the voltage of the battery

Explanation:

The relationship between voltage, V, current, I and resistance, R, is given as follows;

V = I × R

∴ I = V/R

From the above relationship, the current flowing in the circuit is directly proportional to the voltage of the battery, and inversely proportional to the resistance, 'R', of the circuit

Therefore, increasing the voltage, 'V', of the battery, increases the total current, 'I', flowing in the circuit.

7 0
3 years ago
A constant force of 8N acting on an object displaces it through a distance of 3.0 m in the direction of force. Calculate work-do
sweet-ann [11.9K]

\blue{\bold{\underline{\underline{Answer:}}}}

  • \green{\tt{Work\:done=24\:J}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline{\bold{Given :}}} \\  \tt: \implies Constant \: force(F) = 8 \: N \\  \\ \tt: \implies Displacement(s) = 3 \: m \\  \\ \red{\underline{\bold{To \: Find : }}} \\  \tt:  \implies Work \: Done(W.D) = ?

• <u>According to given question</u> :

\green{ \star} \tt \:  \theta \:  = 0 \degree \:  \:  \:  \: (Angle \: between \: force \: and \: displacement) \\  \\  \bold{As \: we \: know \: that} \\  \tt:  \implies Work \: Done = FS \: cos  \: \theta \\  \\  \tt:  \implies Work \: Done = 8 \times 3 \times cos \:0 \degree \\  \\ \green{ \circ} \tt \: cos  \: 0 \degree = 1  \\  \\  \tt:  \implies Work \: Done =24 \times 1 \\  \\   \green{\tt:  \implies Work \: Done =24 \: J}

5 0
3 years ago
. A 2.0-kg block is on a perfectly smooth ramp that makes an angle of 30° with the horizontal. (a) What is the block’s accelerat
AfilCa [17]

Answer:

a) a = 4.9 m / s²,  N = 16.97 N   and b)   F = 9.8 N

Explanation:

a) For this exercise we will use Newton's second law, we write a reference system with the x axis parallel to the plane, see attached, in this system the only force we have to break down is weight, let's use trigonometry

        sin 30 = Wx / W

        cos 30 = Wy / W

        Wx = W sin30

        Wy = W cos 30

Let's write the equations on each axis

X axis

        Wx = ma

Y Axis  

       N- Wy = 0

       N = Wy = mg cos 30

       N = 2.0 9.8 cos 30

       N = 16.97 N

We calculate the acceleration

       a = Wx / m

       a = mg sin 30 / m

       a = g sin 30

       a =9.8 sin 30

       a = 4.9 m / s²

b) For the block to move with constant speed, the acceleration must be zero, so the force applied must be equal to the weight component

      F -Wx = 0

      F = Wx

      F = m g sin 30

      F = 2.0 9.8 sin 30

      F = 9.8 N

5 0
3 years ago
How to convert grams to liters?? V.V? so if your using the weigh machine...and the machine reads in grams and you want liters...
masya89 [10]
You are trying to convert mass to volume. That ain't working
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4 years ago
A 4kg bird is flying with a velocity of 4 m/s. What is its kinetic energy?
Yanka [14]
Kinetic energy = 32 J
8 0
3 years ago
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