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3 years ago

Showing how a projectile motion is parabolic

Physics

1 answer:

evablogger [386]3 years ago

4 0

Answer:

In the equation, d=vi*t+1/2*a*t^2, you can see that this is a quadratic with respect to time, so it follows a parabolic motion

Explanation:

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A rock is rolling down a hill. At position 1, its velocity is 2.0 m/s. Twelve seconds later, as it passes position 2, its veloci

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The acceleration of the rock is 3.5 m/s2

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3 years ago

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10. A force F S 1 of magnitude 6.00 units acts on an object at the ori- gin in a direction u 5 30.0° above the positive x axis (

MArishka [77]

Answer:

The x component of the x axis is: $F_x = F_1\cos(30)=5\cos(30)= 4.33 u$

The y component of the y axis is: $F_y =F_2+ F_1\sin(30)=6.00+5\sin(30)= 8.50 u$

The magnitude is given by: $F = \sqrt{F_x+F_y}= 9.54 u$

The direction is given by: $\theta = \tan^{-1}\frac{F_y}{F_x}= 63.0 ^\circ$

See the graphical magnitude and direction below.

Explanation:

The x component of the x axis is: $F_x = F_1\cos(30)=5\cos(30)= 4.33 u$

The y component of the y axis is: $F_y =F_2+ F_1\sin(30)=6.00+5\sin(30)= 8.50 u$

The magnitude is given by: $F = \sqrt{F_x+F_y}= 9.54 u$

The direction is given by: $\theta = \tan^{-1}\frac{F_y}{F_x}= 63.0 ^\circ$

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3 years ago

Are we the same age as the universe because matter cannot be created nor destroyed

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No. We aren't the same age as the universe.

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4 years ago

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Choose all the answers that apply.

Salsk061 [2.6K]

"Asteroid" is the name we give to the huge number of small bodies
that orbit the sun, here in the inner solar system.

Their orbits are scattered all over the place. Most of them spend
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3 years ago

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A rock, with a density of 3.55 g/cm^3 and a volume of 470 cm^3, is thrown in a lake. a) What is the weight of the rock out of th

SIZIF [17.4K]

Answer:

a) Weight of the rock out of the water = 16.37 N

b) Buoyancy force = 4.61 N

c) Mass of the water displaced = 0.47 kg

d) Weight of rock under water = 11.76 N

Explanation:

a) Mass of the rock out of the water = Volume x Density

Volume = 470 cm³

Density = 3.55 g/cm³

Mass = 470 x 3.55 = 1668.5 g = 1.6685 kg

Weight of the rock out of the water = 1.6685 x 9.81 = 16.37 N

b) Buoyancy force = Volume x Density of liquid x Acceleration due to gravity.

Volume = 470 cm³

Density of liquid = 1 g/cm³

$\texttt{Buoyancy force}= \frac{470\times 1\times 9.81}{1000} = 4.61 N$

c) Mass of the water displaced = Volume of body x Density of liquid

Mass of the water displaced = 470 x 1 = 470 g = 0.47 kg

d) Weight of rock under water = Weight of the rock out of the water - Buoyancy force

Weight of rock under water = 16.37 - 4.61 =11.76 N

3 0

3 years ago

Showing how a projectile motion is parabolic​

Showing how a projectile motion is parabolic