Answer:
0.906 gm/l
Explanation:
We know that molarity of the a solution is given by,
, where 'M' is the molarity, 'w' is the weight of the sample, 'm' is the molar mass, and 'v' is the volume of the solution.
Molarity of a solution tells us the concentration of the solute in the solvent.
Molar mass of KCl is = 74.55
Putting the values we get,
So the molarity of KCl solution is 0.906 gm/l.
Answer:
Kindly check the explanation section.
Explanation:
From the description given in the question above, that is '' H subscript f to the power of degree of the reaction" we have that the description matches what is known as the heat of formation of the reaction, ∆fH° where the 'f' is a subscript.
In order to determine the heat of formation of any of the species in the reaction, the heat of formation of the other species must be known and the value for the heat of reaction, ∆H(rxn) must also be known. Thus, heat of formation can be calculated by using the formula below;
∆H(rxn) = ∆fH°( products) - ∆fH°(reactants).
That is the heat of formation of products minus the heat of formation of the reaction g specie(s).
Say heat of formation for the species is known as N(g) = 472.435kj/mol, O(g) = 0kj/mol and NO = unknown, ∆H°(rxn) = −382.185 kj/mol.
−382.185 = x - 472.435kj/mol = 90.25 kJ/mol
Answer:
Compound: A substance that is made up of more than one type of atom bonded together.
Mixture: A combination of two or more elements or compounds which have not reacted to bond together; each part in the mixture retains its own properties.
Explanation:
The different substances in a mixture are not chemically combined, whereas the different elements in a compound are. The atoms do not combine in the mixture, but they combine when they form a compound.
Hey there!:
As per solubility rules inorganic compounds that are soluble are
:Ammonium (NH4⁺),potassium (K⁺), sodium (Na⁺) : All ammonium, potassium and sodium salts are soluble. Exceptions:some transition metal compounds.
Bromides (Br⁻), chlorides (Cl⁻) and iodides (I⁻): Most bromides are soluble. Exceptions: salts containing silver, lead, and mercury.
So Rb2Cl2 is expected to be soluble.
As per solubility rules inorganic compounds that are insoluble are : Carbonates (CO₃²⁻), chromates (CrO₄²⁻), phosphates (PO₄³⁻), silicates (SiO₄²⁻): All carbonates, chromates, phosphates and silicates are insoluble. Exceptions: those of ammonium, potassium and sodium.
So CaCO3 is insoluble and precipitates
Therefore:
The completed equation is :
Rb2CO3(aq) + CaCl2(aq) → CaCO3(s) + Rb2Cl2(aq)
Hope that helps!