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3 years ago

5

DONT GUESS OR YOUR ANSWER GETS REPORTED!!Students who like information presented to them in a sequential order likely think with

what part of their brains?

1 answer:

Nana76 [90]3 years ago

6 0

the answer is yes and yes

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BONUS QUESTION - It takes 194 mL of a 0.5 M NaOH solution to neutralize 300

Strike441 [17]

Answer:

1.7 mol/dm3

Explanation:

working out in the image

6 0

3 years ago

Assume that the variables x and y are directly related. If k = 8, what is the value for each of the following polnts? Be sure

Ede4ka [16]

Calculus, originally called infinitesimal calculus or "the calculus of infinitesimals", is the mathematical study of continuous change, in the same way that geometry is the study of shape and algebra is the study of generalizations of arithmetic operations.

3 0

3 years ago

A substance has an empirical formula of CH2 and a molar mass of 56 grams per mole. The molecular formula for this compound is

OlgaM077 [116]

<span>(3) C4H8</span>
C=12, H=1
CH2= 12+2=14
(CH2)n=56g/mol
14n=56
n=4
(CH2)4=C4H8

7 0

4 years ago

The string of a bow and arrow is pulled tight

Sloan [31]

Answer:

I'm not sure that is the full question can you show a picture or something?

5 0

3 years ago

Read 2 more answers

Need little help pls

Julli [10]

Answer:

0.354 molal

Explanation:

The molarity (M) or the concentration of a solution is defined as the number of moles of a compound in the solution per liter of solution (mol/L), whereas molality, is defined as the number of moles of a compound in the solution per kg of the compound (mol/kg).

Given that the density of the solution is 1.202 g/mL, which is equivalent to 1.202 kg/L. Since the prefix mili- denotes a factor of one thousandth ( $10^{-3}$ ) and kilo- denotes a factor of one thousand ( ${10}^3$ ),

$1.202 \ \frac{g}{mL} \ = \ 1.202 \ \frac{g}{(10^{-3}) L} \ = \ 1.202 \ \frac{{10}^3g}{L} \ = \ 1.202 \ \frac{kg}{L}$ .

To calculate the corresponding molality of the solution, the formula

$Molality \ (mol/kg) \ = \ \frac{Molarity \ (mol/L)}{Density \ (kg/L)}$ is used.

Therefore,

$Molality \ = \ \frac{0.426 \ mol/L}{1.202 \ kg/L} \ = \ 0.354 \ mol/kg \ \ (3 \ s.f.)$

4 0

3 years ago