I need help ASAP

A brine is used to measure the absolute permeability of a core plug. The rock sample is 4 cm long and 3 cm 2 in cross section. T

nydimaria [60]

Answer : The absolute permeability is, 0.111 darcys.

Explanation : Given,

Volumetric constant rate = $0.5cm^3/s$

Cross section area = $3cm^2$

Pressure = 2 atm

Viscosity = 1.0 cp

Length of rock = 4 cm

From the Darcy equation we conclude that,

$\text{Volumetric constant rate}=\frac{(\text{Absolute permeability}\times A\times P)}{\eta \times l}$

where,

A = cross section area

P = pressure

$\eta$ = viscosity

l = length of rock

Now put all the given values in the above formula, we get:

$0.5cm^3/s=\frac{(\text{Absolute permeability}\times 3cm^2\times 2\text{ atm})}{1.0cp \times 4cm}$

$\text{Absolute permeability}=0.111\text{ darcys}$

Therefore, the absolute permeability is, 0.111 darcys.

8 0

4 years ago

Calculate the density of the rock if its mass is 360 g.

Pavel [41]

Answer:

12.0 g/mL

Explanation:

From the question given above, the following data were obtained:

Mass of Rock = 360 g

Volume of water = 150 mL

Volume of water + Rock = 180 mL

Density of Rock =?

Next, we shall determine the volume of the rock. This can be obtained as follow:

Volume of water = 150 mL

Volume of water + Rock = 180 mL

Volume of Rock =?

Volume of Rock = (Volume of water + Rock) – (Volume of water)

Volume of Rock = 180 – 150

Volume of Rock = 30 mL

Finally, we shall determine the density of the rock as illustrated below:

Mass of Rock = 360 g

Volume of Rock = 30 mL

Density of Rock =?

Density = mass /volume

Density of Rock = 360 / 30

Density of Rock = 12.0 g/mL

Thus, the density of the rock is 12.0 g/mL

4 0

3 years ago

A student working in the laboratory produces 6.81 grams of calcium oxide, CaO, from 20.7 grams of calcium

xz_007 [3.2K]

Answer:

A. Theoretical yield of CaO is 11.59 g

B. Percentage yield of CaO = 58.76%

Explanation:

The following data were obtained from the question:

Mass of CaCO₃ = 20.7 g

Actual yield of CaO = 6.81 g

Theoretical yield of CaO =?

Percentage yield of CaO =?

The equation for the reaction is given below:

CaCO₃ —> CaO + CO₂

Next, we shall determine the mass of CaCO₃ that decomposed and the mass of CaO produced from the balanced equation. This can be obtained as follow:

Molar mass of CaCO₃ = 40 + 12 + (3×16)

= 40 + 12 + 48

= 100 g/mol

Mass of CaCO₃ from the balanced equation = 1 × 100 = 100 g

Molar mass of CaO = 40 + 16 = 56 g/mol

Mass of CaO from the balanced equation = 1 × 56 = 56 g

SUMMARY:

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

A. Determination of the theoretical yield of CaO.

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

Therefore, 20.7 g of CaCO₃ will decompose to produce =

(20.7 × 56)/100 = 11.59 g of CaO.

Thus, the theoretical yield of CaO is 11.59 g

B. Determination of the percentage yield.

Actual yield of CaO = 6.81 g

Theoretical yield of CaO = 11.59 g

Percentage yield of CaO =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 6.81/11.59 × 100

Percentage yield of CaO = 58.76%

4 0

3 years ago

Why would "not flammable" be a chemical property rather than a physical property ?

Dmitrij [34]

When something is flammable, it burns and burning is a chemical property since the compounds are being broken down and gas is released. If something is non-falammable, it would then be a chemical property as well since the chemical makeup would not be broken by a flame. (I apologize if my answer is a bit broad or unspecific)

4 0

3 years ago

14.28 explain how you would distinguish between each pair of compounds using high- resolution mass spectrometry

vagabundo [1.1K]

The distinguish between each pair of compounds using high- resolution mass spectrometry by the exact mass rather than nominal mass are utilizes to measure the compound.

The mass spectrometry is involves the following steps :

The ionization
acceleration
deflection
detection

Mass spectrometry is the analytical method useful for the calculating the mass to charge ratio ( m / z ). the mass spectrometry is based on the newton's second law and the momentum.

Thus, the mass spectroscopy is method to measure the molecular mass of the compound and indirectly helps examine the isotopes and based on the newton's second law .

To learn more about mass spectroscopy here

brainly.com/question/28587595

#SPJ4

7 0

1 year ago