CH4 is an emprirical formula as it shows the simplest ratio of the numbers of different atoms present in the molecule. The empirical formula for CH4 is also the same as the molecular formula.
The other compunds can be simplified so they are not the empirical formula of compounds.
Hope this helps :).

3 0

3 years ago

1. Analysis of an unknown substance formerly used in rocket fuel reveals a composition of 93.28% nitrogen and 6.72% hydrogen by

Nitella [24]

Answer:

The formula of the compound is:

N2H2

Explanation:

Data obtained from the question:

Nitrogen (N) = 93.28%

Hydrogen (H) = 6.72%

Next, we shall determine the empirical formula for the unknown compound. This is illustrated below:

N = 93.28%

H = 6.72%

Divide by their molar mass

N = 93.28 /14 = 6.663

H = 6.72 /1 = 6.7

Divide by the smallest

N = 6.663 / 6.663 = 1

H = 6.72 /6.663 = 1

Therefore, the empirical formula is NH.

Now, we can obtain the formula of the compound as follow:

The formula of a compound is simply a multiple of the empirical formula.

[NH]n = 30.04

[14 + 1]n = 30.04

15n = 30.04

Divide both side by 15

n = 30.04/15

n = 2

Therefore, the formula of the compound is:

[NH]n => [NH]2 => N2H2

6 0

3 years ago

Wood is mainly cellulose, a polymer produced by plants. One use of wood is as a fuel in campfires, fireplaces, and wood furnaces

Alja [10]

Answer:

C6 H10 O5+ 6O2-----> 6CO2+5H2O+heat

Explanation:

There are 6 carbon atoms in reactants to balance you put coefficient 6.

This makes the oxygen in CO2 12 so to balance put 6 in oxygen in reactants.

There are 10 hydrogen atoms in reactants to balance you put 5 in front of H2O in products.

If u recheck: 6 C atoms in reactants, 6 C atoms in products.

10 H atoms in reactants, 10 H atoms in products.

17 O atoms in reactants, 17 O atoms in products.

6 0

2 years ago