Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
20/21 is the answer to your problem.
Answer: 
Explanation: Denominators of a fraction can be equivalently written as their value to the power of negative 1. In this case the denominator expression itself has an exponent of 6, which taken to the power of negative one becomes -6:

I think it would be y=1x+(0-2)