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4 years ago

Consider the equation SO2 → S + O2. The product(s) in this equation would be:

Chemistry

2 answers:

allochka39001 [22]4 years ago

4 0

The products lie on the right hand side of the equation. So, in this case, they are:
S and O₂
The answer is C.

kondaur [170]4 years ago

4 0

Answer: Option (C) is the correct answer.

Explanation:

In a chemical reaction equation, the number of species or molecules written on the left hand side denote reactants whereas the species or molecules written on the right hand side denote products.

For example, in the given equation, $SO_{2} \rightarrow S + O_{2}$ . Left hand side molecule is $SO_{2}$ and it is the reactant. Whereas the molecules or species on right hand side are S and $O_{2}$ and these are the products.

Thus, we can conclude that the product(s) in this equation would be S + O2.

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The two balanced equations (1) and (2) are for reactions in which gaseous carbon dioxide is produced from the combustion of (1)

V125BC [204]

Answer:

2.0 mol of oxygen are consumed.

Step-by-step explanation:

You know that you will need a balanced equation with masses, moles, and molar masses, so gather all the information in one place.

M_r: 28.0 44.0

CO + ½O₂ ⟶ CO₂ + 67.6 kcal

m/g: 112

Step 1. Convert grams of CO to moles of CO

1 mol CO = 28.0 g CO

Moles of CO = 112 × 1/28.0

Step 2. Convert moles of CO to moles of CO₂.

The molar ratio is 1 mol CO₂ to 1 mol CO

Moles of CO₂ = 4.000 × 1/1

Moles of CO₂ = 4.00 mol CO₂

Option A is wrong.

Step 3. Calculate the amount of heat generated.

q = ΔH

The conversion factor is 67.6 kcal/1 mol CO₂

q = 4.00 × 67.6

q = 270 kJ

Option B is wrong, because it gives the heat generated by 1 mol of CO.

Step 4. Calculate the moles of O₂ consumed

Moles of O₂ = 2.00 mol O₂

Option C is correct.

Step 5. Calculate the moles of CO₂ formed

Already done in Step 2.

Moles of CO₂ = 4.00 mol CO₂

Option D is wrong.

Step 6. Calculate the moles of O₂ produced

Already done in Step 4.

Moles of O₂ = 2.00 mol O₂

Option E is wrong. 

3 0

4 years ago

Which statement best expresses Newton's first law of motion? Group of answer choices Objects are constantly speeding up or slowi

nadezda [96]

Answer:

All objects resist changes to their states of motion.

Explanation:

Sir Issac Newton was an English physicist, mathematician, astronomer and a well known author. Besides, he was a great scientist. Newton discovered many scientific phenomenon and scientific theories in nature.

The most important and famous discoveries of Newton is the Newton's laws of motion. Newtons stated three laws of motion, namely, Newtons 1st law of motion, Newton's 2nd laws of motion and Newton's 3rd law of motion.

According to Newtons's 1st law of motion : A body continues to be in the state of motion or in the state of rest until and unless an external force is applied to it. In other words, all bodies resists changes to the states of their motion or rest.

7 0

3 years ago

Material Conductor or Insulator foam insulator aluminum conductor wool insulator ? conductor Which material BEST completes the c

kirill115 [55]

Sorry but i can not decide i think it is B or C

5 0

3 years ago

Silver sulfadiazine burn-treating cream creates a barrier against bacterial invasion and releases antimicrobial agents directly

trapecia [35]

Answer : The mass of silver sulfadiazine produced can be, 71.35 grams.

Solution : Given,

Mass of $Ag_2O$ = 25.0 g

Mass of $C_{10}H_{10}N_4SO_2$ = 50.0 g

Molar mass of $Ag_2O$ = 231.7 g/mole

Molar mass of $C_{10}H_{10}N_4SO_2$ = 250.3 g/mole

Molar mass of $AgC_{10}H_{9}N_4SO_2$ = 357.1 g/mole

First we have to calculate the moles of $Ag_2O$ and $C_{10}H_{10}N_4SO_2$ .

$\text{ Moles of }Ag_2O=\frac{\text{ Mass of }Ag_2O}{\text{ Molar mass of }Ag_2O}=\frac{25.0g}{231.7g/mole}=0.1079moles$

$\text{ Moles of }C_{10}H_{10}N_4SO_2=\frac{\text{ Mass of }C_{10}H_{10}N_4SO_2}{\text{ Molar mass of }C_{10}H_{10}N_4SO_2}=\frac{50.0g}{250.3g/mole}=0.1998moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$Ag_2O(s)+2C_{10}H_{10}N_4SO_2(s)\rightarrow 2AgC_{10}H_9N_4SO_2(s)+H_2O(l)$

From the balanced reaction we conclude that

As, 2 mole of $C_{10}H_{10}N_4SO_2$ react with 1 mole of $Ag_2O$

So, 0.1998 moles of $C_{10}H_{10}N_4SO_2$ react with $\frac{0.1998}{2}=0.0999$ moles of $Ag_2O$

From this we conclude that, $Ag_2O$ is an excess reagent because the given moles are greater than the required moles and $C_{10}H_{10}N_4SO_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $AgC_{10}H_9N_4SO_2$

From the reaction, we conclude that

As, 2 mole of $C_{10}H_{10}N_4SO_2$ react with 2 mole of $AgC_{10}H_9N_4SO_2$

So, 0.1998 mole of $C_{10}H_{10}N_4SO_2$ react with 0.1998 mole of $AgC_{10}H_9N_4SO_2$

Now we have to calculate the mass of $AgC_{10}H_9N_4SO_2$

$\text{ Mass of }AgC_{10}H_9N_4SO_2=\text{ Moles of }AgC_{10}H_9N_4SO_2\times \text{ Molar mass of }AgC_{10}H_9N_4SO_2$

$\text{ Mass of }AgC_{10}H_9N_4SO_2=(0.1998moles)\times (357.1g/mole)=71.35g$

Therefore, the mass of silver sulfadiazine produced can be, 71.35 grams.

8 0

3 years ago

HELPPPPPP!!!!!!!!!!!!!!!!!! NEED SOME HELP PLEASE!!!!!!!!!!!

Sergio039 [100]

Answer:

second

convection current

first

lithosphere

Explanation:

xoxo

Demi

3 0

4 years ago