Answer:
A base.
Explanation:
Basic solutions give OH- ions.
Answer:
1.346 v
Explanation:
1) Fist of all we need to calculate the standard cell potential, one should look up the reduction potentials for the species envolved:
(oxidation)
→
E°=0.337 v
(reduction)
→
E°=1.679 v
(overall)
+8H^{+}_{(aq)}→
E°=1.342 v
2) Nernst Equation
Knowing the standard potential, one calculates the nonstandard potential using the Nernst Equation:
Where 'R' is the molar gas constant, 'T' is the kelvin temperature, 'n' is the number of electrons involved in the reaction and 'F' is the faraday constant.
The problem gives the [red]=0.66M and [ox]=1.69M, just apply to the Nernst Equation to give
E=1.346
Answer:
50.76 mol H2O.
Explanation:
The photosynthesis follows the equation:
6CO2 + 6H2O ---> C6H12O6 + 6O2
This means that 6 mol of H2O are needed to obtain 1 mol of C6H12O6 (see the numbers that precedes every molecule to know how many mols are in game).
So we can say that:
1 mol C6H12O6 --------- 6 mol H2O
8.46 mol C6H12O6 -----x= 8.46 x 6 : 1 = 50.76 mol H20
Gle's cache of http://www.middleschoolchemistry.com/lessonplans/chapter5/lesson4<span>. It is a snapshot of the page as it appeared on 21 Oct 2017 07:24:57 GMT.</span>
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