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3 years ago

Consider the equation SO2 → S + O2. The product(s) in this equation would be:

Chemistry

2 answers:

allochka39001 [22]3 years ago

4 0

The products lie on the right hand side of the equation. So, in this case, they are:
S and O₂
The answer is C.

kondaur [170]3 years ago

4 0

Answer: Option (C) is the correct answer.

Explanation:

In a chemical reaction equation, the number of species or molecules written on the left hand side denote reactants whereas the species or molecules written on the right hand side denote products.

For example, in the given equation, $SO_{2} \rightarrow S + O_{2}$ . Left hand side molecule is $SO_{2}$ and it is the reactant. Whereas the molecules or species on right hand side are S and $O_{2}$ and these are the products.

Thus, we can conclude that the product(s) in this equation would be S + O2.

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In each pair, choose the larger of the indicated quantities or state that the samples are equal:

romanna [79]

<u> There are more total ions in 2.2 moles of </u> $MgCl_2$

Ion, any atom or group of atoms that bears one or more positive or negative electrical charges. Positively charged ions are called cations; negatively charged ions, anions.

Ions are formed by the addition of electrons to, or the removal of electrons from, neutral atoms or molecules or other ions; by combination of ions with other particles; or by rupture of a covalent bond between two atoms in such a way that both of the electrons of the bond are left in association with one of the formerly bonded atoms.

Examples of these processes include the reaction of a sodium atom with a chlorine atom to form a sodium cation and a chloride anion; the addition of a hydrogen cation to an ammonia molecule to form an ammonium cation; and the dissociation of a water molecule to form a hydrogen cation and a hydroxide anion.

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8 0

1 year ago

Ammonia, nh3, for fertilizer is made by causing hydrogen and nitrogen to react at high temperature and pressure. How many moles

charle [14.2K]

Answer:

$0.30molNH_3$

Explanation:

Hello there!

In this case, since the reaction for the formation of ammonia is:

$3H_2+N_2\rightarrow 2NH_3$

We can evidence the 1:2 mole ratio of nitrogen gas to ammonia; therefore, the appropriate stoichiometric setup for the calculation of the moles of the latter turns out to be:

$0.15molN_2*\frac{2molNH_3}{1molN_2}$

And the result is:

$0.30molNH_3$

Best regards!

7 0

2 years ago

If an unknown element displays many extremely strong metallic properties, where is it most likely to be located on the periodic

dalvyx [7]

It is placed on the far left. Hope I helped:)

3 0

2 years ago

Read 2 more answers

How many moles are in 29.5 grams of Ax?

JulsSmile [24]

The number of moles present in 29.5 grams of argon is 0.74 mole.

The atomic mass of argon is given as;

Ar = 39.95 g/mole

The number of moles present in 29.5 grams of argon is calculated as follows;

39.95 g ------------------------------- 1 mole

29.5 g ------------------------------ ?

$= \frac{29.5}{39.95} \\\\= 0.74 \ mole$

Thus, the number of moles present in 29.5 grams of argon is 0.74 mole.

<em>"Your question seems to be missing the correct symbol for the element" </em>

Argon = Ar

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6 0

2 years ago

To measure the speed of a car, we use miles per hour (miles/hour or mi/h or mph). To measure the rate of a reaction we use molar

arsen [322]

Answer:

Part A: 47.8 mi/h

Part B: 0.072 M/s

Part C: 0.144 M/s

Explanation:

Part A

The average speed or velocity (V) is the variation of the space divided by the variation of the time:

V = (241 - 2)/(8 -3)

V = 47.8 mi/h

Part B

As Part A, the average rate (r) of formation of I2 is the variation of the concentration divided by the variation of time:

r = (1.83 - 1.11)/(15 - 5)

r = 0.072 M/s

Part C

The rates of the substances are proportional of their number of moles (n) which are their coefficient, so:

rI2/nI2 = rHCl/nHCl

0.072/1 = rHCl/2

rHCl = 2*0.072

rHCl = 0.144 M/s

7 0

2 years ago