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eimsori [14]
3 years ago
5

Does gravity exist without air?

Chemistry
1 answer:
sveticcg [70]3 years ago
3 0

Mass is required for gravity. Higher mass implies higher gravitational drag. Most of these thoughts are tied to other planets without atmospheres, or the moon. The moon doesn't have any air or atmosphere and it pulls the Earth water.

Please correct any mistakes in my answer!! I'd be happy to fix it!! :)

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Balance the following redox reaction if it occurs in basic solution. What are the coefficients in front of Br2 and OH- in the ba
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Br2(l) → BrO3-(aq) + Br-(aq)

A) Br2 = 3, OH - = 6

B) Br2 = 3, OH - = 3

C) Br2 = 2, OH - = 5

D) Br2 = 1, OH - = 2

E) Br2 = 1, OH - = 6

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How were the elements in the first periodic table arranged? O A. In order of atomic number B. Alphabetically by element name C.
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6 0
4 years ago
What mass of iron(II) oxide must be used in the reaction given by the equation below to release 44.7 kJ? 6FeO(s) + O2(g) => 2
zavuch27 [327]

<u>Answer:</u> The mass of iron (II) oxide that must be used in the reaction is 30.37

<u>Explanation:</u>

The given chemical reaction follows:

6FeO(s)+O_2(g)\rightarrow 2Fe_3O_4(s);\Delta H^o=-635kJ

By Stoichiometry of the reaction:

When 635 kJ of energy is released, 6 moles of iron (II) oxide is reacted.

So, when 44.7 kJ of energy is released, \frac{6}{635}\times 44.7=0.423mol of iron (II) oxide is reacted.

Now, calculating the mass of iron (II) oxide by using the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of iron (II) oxide = 0.423 moles

Molar mass of iron (II) oxide = 71.8 g/mol

Putting values in above equation, we get:

0.423mol=\frac{\text{Mass of FeO}}{71.8g/mol}\\\\\text{Mass of FeO}=(0.423mol\times 71.8g/mol)=30.37g

Hence, the mass of iron (II) oxide that must be used in the reaction is 30.37

7 0
4 years ago
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