Q1. TI (210/81Thallium)
Q2.
The answers are opposite from each other
It forms Carbon monoxide.
CO2 +O2⇒ CO
(Sorry not balanced)
Answer:
2 C₄H₁₀(l) + 13 O₂(g) ⇄ 8 CO₂(g) + 10 H₂O(g)
Explanation:
When a substance burns we talk about a combustion reaction. When combustion is complete the products are carbon dioxide and water, like in this case. The equation is:
C₄H₁₀(l) + O₂(g) ⇄ CO₂(g) + H₂O(g)
First, we balance the element with the largest stoichiometric coefficient (C).
C₄H₁₀(l) + O₂(g) ⇄ 4 CO₂(g) + H₂O(g)
Then, we balance H because it is in just 1 compound on each side.
C₄H₁₀(l) + O₂(g) ⇄ 4 CO₂(g) + 5 H₂O(g)
Finally, we balance O.
C₄H₁₀(l) + 6.5 O₂(g) ⇄ 4 CO₂(g) + 5 H₂O(g)
Since we want the smallest whole numbers, we multiply all coefficients by 2.
2 C₄H₁₀(l) + 13 O₂(g) ⇄ 8 CO₂(g) + 10 H₂O(g)
Answer:
= C3H4N
Explanation:
We are given; 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen.
We first calculate the number of moles of each element.
Carbon = 90g/12 g/mol
= 7.5 moles
Hydrogen = 11 g/ 1 g/mol
= 11 moles
Nitrogen = 35 g/ 14 g/mol
= 2.5 moles
The we get the mole ratio of the elements;
= 7.5/2.5 : 11/2.5 : 2.5 /2.5
= 3 : 4.4 : 1
= 3 : 4 : 1
Therefore;
The empirical formula will be; C3H4N
