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Ivan
4 years ago
12

Metrology as a study of

Chemistry
2 answers:
Sophie [7]4 years ago
5 0

Weather

Explanation:

Meteorology is the study of weather.

Meteorologists are scientists that helps to predict weather phenomenon around us.

The use several data gathered from different weather stations around to make precise predictions about the likelihood of a particular weather condition.

Meteorologists most times use computer models to predict and forecast both long and short term weather conditions.

learn more:

Weather brainly.com/question/1851697

#learnwithBrainly

tigry1 [53]4 years ago
3 0

Answer: measurement

Explanation: meteorology is the study of weather but metrology is what it is asking for which is the study of measurement

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newtons 3rd law of motion

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What molecular formulas has the same empirical formula
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each molecule of which consists of one carbon atom, two hydrogen atoms, and one oxygen atom, has the molecular formula CH2O, which is identical to the empirical formula of glucose.

If this helps.

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Say the Tuna is removed from the ocean food web, how would it affect other organisms in the food web?
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removing a top predator may cause its prey to become more abundant, as fewer individuals are eaten. But with more prey around, the organisms that it eats may become scarcer. Seemingly simple changes can have complex effects, with direct and indirect interactions rippling throughout entire ecosystems.

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4 years ago
How do forces between particles in gases compare to forces in the other states of matter?​
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3 years ago
The argon atoms are excited into an excited state before emitting the 488.0 nm laser. It is known that the energy of the first i
Jobisdone [24]

Answer:

Explanation:

Given that:

The argon atoms are excited into an excited state before emitting the 488.0 nm laser.

the energy of the first ionization energy of argon is 1520 kJ mol-1.

SInce 1 eV = 96.49 kJ/mol

Therefore, the energy of the first ionization energy of argon in eV is = ( 1520/ 96.49) eV

=  15.75 eV

To find where  the energy level of the excited state lies below the vacuum energy level, let's first determine, the energy liberated by using planck expression.

E = \dfrac{hc}{\lambda}

E  = \dfrac{6.6 \times 10^{-34} \times 3 \times 10^8}{488 \times 10^{-9}}

E  = \dfrac{1.98 \times 10^{-25}}{488 \times 10^{-9}}

E  = \dfrac{1.98 \times 10^{-25}}{488 \times 10^{-9}}

E  =4.057 \times 10^{-19} \ J

Converting Joules (J) to eV ; we get,

E  =\dfrac{4.057 \times 10^{-19}}{1.6 \times 10^{-19}}

E = 2.53 eV

The energy levels of the first exited state = -13.223 eV

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4 years ago
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