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kodGreya [7K]
3 years ago
10

e average bond order is the number of bonds between two atoms taking into account resonance. Draw a Lewis structure for ozone an

d answer the questions below. 1. There are equivalent Lewis structures for O3 . (number) 2. The average O - O bond order is
Chemistry
1 answer:
sineoko [7]3 years ago
5 0

Answer:

See Explanation

Explanation:

Resonance is a valence bond terminology which is used to describe a situation in which a single structure is not able to fully describe the nature of bonding in a molecule.

In such cases, we invoke more than one structure. Each structure contributes significantly to our understanding of the nature of bonding in the molecule under consideration and these structures are called canonical or resonance structures.

The real structure of the molecule is somewhere in between these structures -  a resonance hybrid.

For ozone, two equivalent structures can be used to describe the bonding in the molecule. These structures are equivalent as shown in the mage attached. We can see from these structures that the bond order in ozone is 1.5(one and half bonds)

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The substances below are listed by increasing specific heat capacity value. Starting at 30 Celsius, they absorb 100 kJ of therma
Georgia [21]

Answer:

Silver.

Explanation:

To obtain the right answer to question, let us calculate the change in temperature for each substance assuming they all have the same mass as 100g.

This is illustrated below:

1. For Siver:

Mass (M) = 100g

Specific heat capacity (C) = 0.239J/g°C

Heat (Q) = 100 kJ = 100000J

Change in temperature (ΔT)

Q = MCΔT

ΔT = Q/MC

ΔT = 100000/(100 x 0.239)

ΔT = 4184°C

2. For Aluminium:

Mass (M) = 100g

Specific heat capacity (C) = 0.921J/g°C

Heat (Q) = 100 kJ = 100000J

Change in temperature (ΔT)

Q = MCΔT

ΔT = Q/MC

ΔT = 100000/(100 x 0.921)

ΔT = 1086°C

3. For Lithium:

Mass (M) = 100g

Specific heat capacity (C) = 3.56J/g°C

Heat (Q) = 100 kJ = 100000J

Change in temperature (ΔT)

Q = MCΔT

ΔT = Q/MC

ΔT = 100000/(100 x 3.56 )

ΔT = 281°C

4. For water:

Mass (M) = 100g

Specific heat capacity (C) = 4.184J/g°C

Heat (Q) = 100 kJ = 100000J

Change in temperature (ΔT)

Q = MCΔT

ΔT = Q/MC

ΔT = 100000/(100 x 4.184)

ΔT = 239°C

Summary

Temperature change of each substance is given below

1. Silver => 4184°C

2. Aluminum => 1086°C

3. Lithium => 281°C

4. Water => 239°C

From the calculations made above, Silver has the highest rise in temperature.

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