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lubasha [3.4K]
3 years ago
5

F= 1/3 and A=1 please help me with this math promblem

Mathematics
2 answers:
Aleks04 [339]3 years ago
6 0
[(1/3)^-2]/5*1=[(1/(1/3)^2)]/5=9/5



..................................................................
Studentka2010 [4]3 years ago
5 0
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\
-------------------------------\\\\
\cfrac{f^{-2}}{5a}\quad 
\begin{cases}
a=1\\
f=\frac{1}{3}
\end{cases}\implies \cfrac{\left( \frac{1}{3} \right)^{-2}}{5(1)}\implies \cfrac{\left( \frac{3}{1} \right)^{2}}{5(1)}\implies \cfrac{\frac{3^2}{1^2}}{5}\implies \cfrac{9}{5}
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x=7

Step-by-step explanation:

7=2x-7

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7 0
1 year ago
Aria drank 500 milliliters of water after her run. Her best friend, Andrea, drank 0.75 liter of water. Who drank more?
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8 0
3 years ago
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Digiron [165]
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5 0
3 years ago
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Oksi-84 [34.3K]

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Pani-rosa [81]

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To find the inverse, you need to switch the f(x) and x in the equation. Then you can solve for the new f(x). The result will be the inverse (f-1)

f(x) = 3x + 1 ----> Switch f(x) and x

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f-1(6) = 5/3

3 0
3 years ago
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