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Sphinxa [80]
3 years ago
8

A jet airplane is traveling west from Austin, Texas to Miami, Florida. It has an average speed with no wind of 600 mph. An obser

ver on the ground records the airplane of having a speed of 580 mph. What speed and direction is the wind moving?
Physics
2 answers:
katrin [286]3 years ago
7 0

consider the west direction as positive direction of motion

V' = velocity of airplane relative to observer on ground = 580 mph

v = velocity of wind relative to observer on ground

V = average speed of airplane with no wind = 600 mph

relative velocity is given as

V' = V + v

inserting the values

580 = 600 + v

v = 580 - 600

v = - 20 mph

the negative sign indicates the direction of wind is opposite to direction of airplane , east

hence speed of wind is 20 mph in east direction.


k0ka [10]3 years ago
7 0

Velocity of airplane without any wind

v_1 = 600 mph

now when air is blowing with some speed then the net speed is observed by the observer

v_{net} = 580 mph

now we will have

v_{net} = v_1 - v_w

wind speed here is given as v_w

now here we will have

580 = 600 - v_w

v_w = 20 mph

so wind speed will have 20 mph

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Answer:

208.33 W

141.26626 seconds

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P=\frac{E}{t}\\\Rightarrow P=\frac{6\times 10^6}{8\times 60\times 60}\\\Rightarrow P=208.33\ W

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Two charged point-like objects are located on the x-axis. The point-like object with charge q1 = 4.60 µC is located at x1 = 1.25
mylen [45]

Answer:

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b) the total electric potential (in V) at the point with coordinates (0, 1.50 cm) is 1330769.23 V

Explanation:

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a) Determine the total electric potential (in V) at the origin.

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Vp = V1 + V2

Vp = kq1/r1 + kq2/r2

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b)

the total electric potential (in V) at the point with coordinates (0, 1.50 cm).

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r1 = √[ 0.015² + 0.0125² ]

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r2 = √[ 0.015² + 0.018² ]

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we substitute

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Vp = 2123076.923 + ( -762962.962 )

Vp = 2123076.923 -792307.692

Vp =  1330769.23 V

Therefore, the total electric potential (in V) at the point with coordinates (0, 1.50 cm) is 1330769.23 V

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