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Sphinxa [80]
4 years ago
8

A jet airplane is traveling west from Austin, Texas to Miami, Florida. It has an average speed with no wind of 600 mph. An obser

ver on the ground records the airplane of having a speed of 580 mph. What speed and direction is the wind moving?
Physics
2 answers:
katrin [286]4 years ago
7 0

consider the west direction as positive direction of motion

V' = velocity of airplane relative to observer on ground = 580 mph

v = velocity of wind relative to observer on ground

V = average speed of airplane with no wind = 600 mph

relative velocity is given as

V' = V + v

inserting the values

580 = 600 + v

v = 580 - 600

v = - 20 mph

the negative sign indicates the direction of wind is opposite to direction of airplane , east

hence speed of wind is 20 mph in east direction.


k0ka [10]4 years ago
7 0

Velocity of airplane without any wind

v_1 = 600 mph

now when air is blowing with some speed then the net speed is observed by the observer

v_{net} = 580 mph

now we will have

v_{net} = v_1 - v_w

wind speed here is given as v_w

now here we will have

580 = 600 - v_w

v_w = 20 mph

so wind speed will have 20 mph

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3 years ago
A source emits sound with a frequency of 16246 Hz. Both it and an observer are moving toward each other, each with a speed of 14
nasty-shy [4]

Answer:

39267.96 Hz

Explanation:

Given:

Frequency emitted = 16246 Hz

Speed of source = 141 m/s

Speed of observer = 141 m/s

Let the velocity of sound is v = 340 m/s

Doppler effect is nothing but the change in the wavelength or frequency of a wave relative to the observer, who is also moving relative to the origin of the wave source.

Therefore, Doppler effect when the source and the observer moves towards each other,

Frequency heard = ( frequency emitted ) ( Velocity of sound + Speed of the observer ) / ( velocity of sound - speed of source )

                      16246 x ( 340 + 141 ) / ( 340 - 141 )

                         = 39267.96 Hz

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a stone is thrown horizonttaly from a cliff of a hill with an initial velocity of 30m/s it hits the ground at a horizontal dista
ELEN [110]

Answer:

a) Time = 2.67 s

b) Height = 35.0 m

Explanation:

a) The time of flight can be found using the following equation:

x_{f} = x_{0} + v_{0_{x}}t + \frac{1}{2}at^{2}   (1)

Where:

x_{f}: is the final position in the horizontal direction = 80 m

x_{0}: is the initial position in the horizontal direction = 0

v_{0_{x}}: is the initial velocity in the horizontal direction = 30 m/s

a: is the acceleration in the horizontal direction = 0 (the stone is only accelerated by gravity)

t: is the time =?  

By entering the above values into equation (1) and solving for "t", we can find the time of flight of the stone:  

t = \frac{x_{f}}{v_{0}} = \frac{80 m}{30 m/s} = 2.67 s

b) The height of the hill is given by:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

Where:

y_{f}: is the final position in the vertical direction = 0

y_{0}: is the initial position in the vertical direction =?

v_{0_{y}}: is the initial velocity in the vertical direction =0 (the stone is thrown horizontally)            

g: is the acceleration due to gravity = 9.81 m/s²

Hence, the height of the hill is:

y_{0} = \frac{1}{2}gt^{2} = \frac{1}{2}9.81 m/s^{2}*(2.67 s)^{2} = 35.0 m  

I hope it helps you!

5 0
3 years ago
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