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denis-greek [22]
3 years ago
13

HELP ASAP I WILL GIVE BRAINLIEST!!!!!!!!!!!

Physics
1 answer:
Mice21 [21]3 years ago
5 0
Ok the answer for this question would be B. Hope this helps.

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When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the
nataly862011 [7]

Answer:

Given: V=12 V

            I=2.5 mA

Let the resistance be R

By Ohm's Law, 

V=IR

12=2.5×10−3R

R=4.8×103 Ω

8 0
3 years ago
Our eyes can detect light only within a range of ____________ called visible light. frequencies speeds mediums periods
ahrayia [7]

Our eyes detect light only within a range of frequencies called visible light.

3 0
3 years ago
Why can concave mirror is used in cosmetic mirror​
tatuchka [14]

Answer:

"When face is placed between the concave mirror and its focus, it produces a magnified image. This enlarged image of face is helpful in makeup as even pores of skin are clearly visible."

4 0
3 years ago
The photometer is a device that converts light to voltage which is read out by the digital multimeter (DMM). This is due to the
dimaraw [331]

Answer:

It converts light into electric current.

Explanation:

The first line of the description says that the photometer is a device that converts light to voltage. if the voltage can be measured then current flowing through it can be calculated by Ohms law V=IR.

<em>Hence the photometer converts light to electric current.</em>

The photometer is used to measure the strength of electromagnetic radiation falling on it and operate within the range of ultraviolet ,visible and infrared spectrum.

It converts light to electric current using photodiode (pn junction),photoresistor and photmultiplier.

 

8 0
3 years ago
A cannonball is fired in such a way
Goryan [66]

Answer:

θ = 53.13° above horizontal

Explanation:

Ignore air resistance.

The time the ball takes to reach its max height will equal the time to travel half the max range R.

√(2h/g) = (R/2)/vcosθ

vsinθ/g = R/2vcosθ

2v²sinθcosθ = Rg

2v²sinθcosθ = 3hg

v² = u² + 2gh

0² = v²sin²θ + 2gh

v²sin²θ = 2gh

v² = 2gh/sin²θ

               2v²sinθcosθ = 3hg

(2gh/sin²θ)2sinθcosθ = 3hg

            (2/sinθ)2cosθ = 3

                            cotθ = 3/4

                                 θ = 53.130

5 0
3 years ago
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