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4 years ago

Explain why diamonds are useful for electrodes in batteries

Chemistry

1 answer:

umka21 [38]4 years ago

8 0

Answer:

Diamonds have a broader potential window of 3 to 5 volts.

Explanation:

The minimum voltage required for electrolysis is called potential window. Electrodes such as titanium electrodes and those made of noble metals have a potential window of about 2 volts. Diamond has a potential window of 3 to 5 volts that makes it preferentially start a redox reaction of a substance that is difficult to electrolyze. This facilitates electrolysis of substance that were difficult to decompose in normal electrochemical systems.

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How are characteristic properties of matter used to it different matter?

Lisa [10]

Answer:

You can tell types of matter apart based on their properties. Physical properties of matter can be observed or measured without changing the identity of the substance.... Characteristic physical properties are properties that are always the same for a substance - so they can be used to identify a substance.

Explanation:

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3 years ago

Which prefix is the smallest?

Ann [662]

Answer:could it be kilo

Explanation:it looks like it has the least letters

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3 years ago

According to the law of superposition, which statements are supported by the diagram? Check all that apply.

Doss [256]

Answer:

A B D

Explanation:

8 0

3 years ago

Read 2 more answers

Lithium salts are often much less soluble in water than the corresponding salts of other alkali metals. For example, at 18°C, th

serious [3.7K]

Lithium is one of element of group 1 of periodic table.

Lithium has the smallest radius than as compared to the other elements, thus the density of the alkali metal is also less.

Lithium when added to water it floats, because of lower density. It eventually fizzes and becomes smaller.

The reaction on lithium and water is:

2Li + 2H₂O --> 2LiOH + H₂ (g)

The hydrogen gas which is liberated is highly flammable.

Thus, lithium salts are insoluble in water.

Density is defined as the mass of a substance per unit volume.

Density = Mass ÷ Volume.

To know more about Alkali metals, refer to this link:

brainly.com/question/5063184

#SPJ4

8 0

1 year ago

A solution was prepared by dissolving 28.0g of KCL in 225g of water. Part A Calculate the mass percent ofKCL in the solution. Pa

Westkost [7]

Answer:

A. 11.1%

B. 0.0291

C. 1.57 M

D. 1.67 m

Explanation:

Mass of KCl (solute): 28.0 g

Mass of water (solvent): 225 g

Mass of solution: 28.0 g + 225 g = 253 g

The mass percent of KCl is:

%KCl = (mass of KCl/mass of solution) × 100%

%KCl = (28.0 g/253 g) × 100%

%KCl = 11.1%

The molar mass of KCl is 74.55 g/mol. The moles of KCl are:

28.0 g × (1 mol/74.55 g) = 0.376 mol

The molar mass of water is 18.02 g/mol. The moles of water are:

225 g × (1 mol/18.02 g) = 12.5 mol

The total number of moles is 0.376 mol + 12.5 mol = 12.9 mol.

The mole fraction of KCl is:

X(KCl) = moles of KCl / total moles

X(KCl) = 0.376 mol / 12.9 mol

X(KCl) = 0.0291

The volume of the solution is 239 mL (0.239 L).

The molarity of KCl is:

M = moles of KCl / liters of solution

M = 0.376 mol / 0.239 L

M = 1.57 M

The molality of KCl is:

m = moles of KCl / kilograms of solvent

m = 0.376 mol / 0.225 kg

m = 1.67 m

4 0

4 years ago