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2 years ago

The goal of the Human Genome Project was to _____.

Chemistry

2 answers:

ahrayia [7]2 years ago

6 0

<h3>Question :</h3>

The goal of the Human Genome Project was to _____.

locate specific genes that caused given diseases

identify the RNA of the human genome

promote friendliness among the various sciences

map the entire human genome

<h3>Answer : </h3>

The goal of the Human Genome Project was to <u>map the entire human genome</u><u>.</u>

So, the correct option is 4th one.

svp [43]2 years ago

6 0

Answer:

bioethicist

one who studies the ethics involved in areas of biology

biotechnology

the use of biological structures and processes for useful industrial purposes, whether product or function

chromosome

condensed structures made up of DNA and protein found in the nucleus when a eukaryotic cell is preparing to divide

DNA

nucleic acids that carry the genetic code

Explanation

My teacher did not teach me this but I feel like this is the right answer because I took a test and got the answer right using the same answer

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In the reaction 2 FeBr3 + 3 Cl2 → 2 FeCl3 + 3 Br2, how many grams of bromine gas are produced from 2.50 moles of FeBr3?

posledela

Answer:

but iron is 2 and 3 by its valance how could it be possible

4 0

2 years ago

Calculate the density of air at 100 Deg C and 1 bar abs. Use the Ideal Gas Law for your calculation and give answer in kg/m3. Us

madam [21]

Answer:

$d=0.92\frac{kg}{m^{3}}$

Explanation:

Using the Ideal Gas Law we have $PV=nRT$ and the number of moles n could be expressed as $n=\frac{m}{M}$ , where m is the mass and M is the molar mass.

Now, replacing the number of moles in the equation for the ideal gass law:

$PV=\frac{m}{M}RT$

If we pass the V to divide:

$P=\frac{m}{V}\frac{RT}{M}$

As the density is expressed as $d=\frac{m}{V}$ , we have:

$P=d\frac{RT}{M}$

Solving for the density:

$d=\frac{PM}{RT}$

Then we need to convert the units to the S.I.:

$T=100^{o}C+273.15$

$T=373.15K$

$P=1bar*\frac{0.98atm}{1bar}$

$P=0.98atm$

$M=28.9\frac{kg}{kmol}*\frac{1kmol}{1000mol}$

$M=0.0289\frac{kg}{mol}$

Finally we replace the values:

$d=\frac{(0.98atm)(0.0289\frac{kg}{mol})}{(0.082\frac{atm.L}{mol.K})(373.15K)}$

$d=9.2*10^{-4}\frac{kg}{L}$

$d=9.2*10^{-4}\frac{kg}{L}*\frac{1L}{0.001m^{3}}$

$d=0.92\frac{kg}{m^{3}}$

5 0

3 years ago

What did you observe<br> when heat was added to the penny with iodine?

Andru [333]

This is a difficult task because zinc is much more active than copper and could hardly be passivated. ... The sur- face immediately turns white (the color of copper(I) iodide) and the yellow-brown color of iodine quickly fades. Rinse the coin with water, brighten it with polish and cloth and begin the whole process again.N

8 0

2 years ago

What are standards or attributes of a design that can be measured.

ankoles [38]

Explanation:

attribute of a person that often cannot be measured directly but can be assessed using numbers of indicators or manifest variables

4 0

2 years ago

Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:

posledela

Answer: The value of the equilibrium constant Kc for this reaction is 3.72

Explanation:

Equilibrium concentration of $HNO_3$ = $\frac{15.5g}{63g/mol\times 9.5L}=0.026M$

Equilibrium concentration of $NO$ = $\frac{16.6g}{30g/mol\times 9.5L}=0.058M$

Equilibrium concentration of $NO_2$ = $\frac{22.5g}{46g/mol\times 9.5L}=0.051M$

Equilibrium concentration of $H_2O$ = $\frac{189.0g}{18g/mol\times 9.5L}=1.10M$

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_c$

For the given chemical reaction:

$2HNO_3(aq)+NO(g)\rightarrow 3NO_2(g)+H_2O(l)$

The expression for $K_c$ is written as:

$K_c=\frac{[NO_2]^3\times [H_2O]^1}{[HNO_3]^2\times [NO]^1}$

$K_c=\frac{(0.051)^3\times (1.10)^1}{(0.026)^2\times (0.058)^1}$

$K_c=3.72$

Thus the value of the equilibrium constant Kc for this reaction is 3.72

5 0

2 years ago