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Snowcat [4.5K]
3 years ago
7

A compound with the empirical formula CH2 has a molar mass of 126g/mol. What is the molecular formula for this compound?

Chemistry
2 answers:
Talja [164]3 years ago
5 0

Answer:

The compound has a molecular formula of C9H18

Explanation:

Step 1: Data given

the compound has an empirical formula of CH2

The molar mass of the compound is 126 g/mol

Molar mass C = 12 g/mol

Molar mass H = 1 g/mol

Step 2: Calculate the molar mass of the empirical formula

We have 1x C and 2x H

Molar mass = 1*12 + 2*1 = 14 g/mol

Step 3: Calculate the molecular formula

126 / 14 = 9

We have to multiply the empirical formula by 9 to have the molecular formula

9*(CH2) = C9H18

The compound has a molecular formula of C9H18

stellarik [79]3 years ago
3 0

Answer: C10H20

Explanation:

C=12

H=1

(12+1)n=126

13n=126

n=126/13

n=10

Molecular formula

C10H20

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Answer:

2.35

Explanation:

<em>A 1.00-L flask was filled with 2.00 moles of gaseous SO₂ and 2.00 moles of gaseous NO₂ and heated. After equilibrium was reached, it was found that 1.21 moles of gaseous NO was present. Assume that the reaction </em>

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<em>occurs under these conditions. Calculate the value of the equilibrium constant, K, for this reaction.</em>

<em />

Step 1: Calculate the molar concentrations

Since the reaction takes place in a 1.00 L flask, the molar concentrations are:

[SO₂]i = 2.00 M

[NO₂]i = 2.00 M

[NO]eq = 1.21 M

Step 2: Make an ICE chart

        SO₂ + NO₂ ⇌ SO₃ + NO

I       2.00   2.00       0        0

C        -x       -x         +x       +x

E    2.00-x  2.00-x    x         x

Step 3: Calculate the concentrations at equilibrium

The concentration of NO at equilibrium is 1.21 M. Then, x = 1.21.

[SO₂]eq = 2.00-1.21 = 0.79 M

[NO₂]eq = 2.00-1.21 = 0.79 M

[SO₃]eq = x = 1.21 M

[NO]eq = x = 1.21 M

Step 4: Calculate the value of the equilibrium constant, K, for this reaction

K = [SO₃] × [NO]/[SO₂] × [NO₂]

K = 1.21²/0.79² = 2.35

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