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Georgia [21]
4 years ago
13

Which location is MOST LIKELY to be struck by a hurricane? A) Charleston, South Carolina B) San Diego, California C) Buffalo, Ne

w York D) Wichita, Kansas
Physics
1 answer:
xxTIMURxx [149]3 years ago
6 0

It is A) Charleston because it is the closest city to warm Atlantic waters.

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Which is the last stage in the life cycle of an average star? (1 point)
Shkiper50 [21]

Answer:

The answer is A. White Dwarf

Explanation:

  • <u>average stars like sun end their life as white dwarf surrounded by disappearing planetary nebula. </u>
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2 years ago
Is torque only produced when the force is applied perpendicular to the moment arm?
trasher [3.6K]
Yes. Only a perpendicular component produces a torque.
8 0
3 years ago
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Which of the following is not a compound <br> A. Gold <br> B. Water<br> C. Salt<br> D. Sugar
skelet666 [1.2K]

Answer:

Gold

Explanation:

Water is H20

Salt is NaCl

Sugar is C12H22O11

Gold is Au with no other elements

6 0
3 years ago
you slide abox of books at constant speed up a30 degree ramp, applying a force of 200 newtons directed up the slope. The coeffic
Tomtit [17]

The work done is 400 J

Explanation:

The work done by you in pushing the box along the slope is given by

W=Fd

where

F is the magnitude of the force applied

d is the distance covered by the box along the slope

Here we have the following:

F = 200 N is the magnitude of the force applied

d=\frac{h}{sin \theta} is the distance covered, where

h = 1 m is the vertical rise

\theta=30^{\circ} is the slope of the plane

Substituting and solving, we find

W=F\frac{h}{sin \theta}=\frac{(200)(1)}{sin 30^{\circ}}=400 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

5 0
3 years ago
Eac of the two Straight Parallel Lines Each of two very long, straight, parallel lines carries a positive charge of 24.00 m C/m.
Cloud [144]

Answer:

The magnitude of the electric field at a point equidistant from the lines is 4.08\times10^{5}\ N/C

Explanation:

Given that,

Positive charge = 24.00  μC/m

Distance = 4.10 m

We need to calculate the angle

Using formula of angle

\theta=\sin^{-1}(\dfrac{\dfrac{d}{2}}{2d})

\theta=\sin^{-1}(\dfrac{1}{4})

\theta=14.47^{\circ}

We need to calculate the magnitude of the electric field at a point equidistant from the lines

Using formula of electric field

E=\dfrac{2k\lambda}{r}\times2\cos\theat

Put the value into the formula

E=\dfrac{2\times9\times10^{9}\times24.00\times2\times10^{-6}\cos14.47}{2.05}

E=408094.00\ N/C

E=4.08\times10^{5}\ N/C

Hence, The magnitude of the electric field at a point equidistant from the lines is 4.08\times10^{5}\ N/C

6 0
3 years ago
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