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Vladimir [108]
3 years ago
11

The weight of a box having a mass of 100 kg is blank N

Physics
1 answer:
erastova [34]3 years ago
4 0

Answer:980 N

Explanation:

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A plane wall of thickness 0.1 mm and thermal conductivity 25 W/m K having uniform volumetric heat generation of 0.3 MW/m3 is ins
juin [17]

Answer:

The maximum temperature is 90.06° C

Explanation:

Given that

t= 0.1 mm

Heat generation

q_g=0.3\ MW/m^3

Heat transfer coefficient

h=500\ W/m^2K

Here one side(left side) of the wall is insulated so the all heat will goes in to right side .

The maximum temperature will at the left side.

Lets take maximum temperature is T

Total heat flux ,q

q=q_g\times t

q=0.3\times 1000000\times 0.1 \times 10^{-3}\ W/m^2

q=30\ W/m^2

So the total thermal resistance per unit area

R=\dfrac{t}{K}+\dfrac{1}{h}

R=\dfrac{0.1\times 10^{-3}}{25}+\dfrac{1}{500}

R=0.002 K/W

We know that

q=ΔT/R

30=(T-90)/0.002

T=90.06° C

The maximum temperature is 90.06° C

3 0
2 years ago
A tool industry characterized by the appearance of hand axes, a bifacial type of blade.
marshall27 [118]
The stone tool industry being described is the Acheulean. These tools are characterized by hand axes and bifacial blades and were made by many different species of Homos, including Homo erectus and early Homo sapiens.
7 0
3 years ago
What does a cell use to eliminate a substance that is too large to leave by diffusion?
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<span>a cell eliminates endocytosis.

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3 years ago
Define about the different types of silk found around the world
Sunny_sXe [5.5K]

Answer:

In short, there are four types of natural silk produced around the world: Mulberry silk, Eri silk, Tasar silk and Muga silk. Mulberry silk contributes around as much as 90% of silk production, with the mulberry silkworm generally being regarded as the most important.

7 0
2 years ago
What is the maximum value of the magnetic field at a distance of 2.5 m from a light bulb that radiates 100 W of single-frequency
Anvisha [2.4K]

Answer:

1.04\times 10^{-7} T

Explanation:

IP  = Power of the bulb = 100 W

r  = distance from the bulb = 2.5 m

I = Intensity of light at the location

Intensity of the light at the location is given as

I = \frac{P}{4\pi r^{2}}

I = \frac{100}{4(3.14) (2.5)^{2}}

I = 1.28 W/m²

B_{o} = maximum magnetic field

Intensity is given as

I = \frac{B_{o}^{2}c}{2\mu _{o}}

1.28 = \frac{B_{o}^{2}(3\times 10^{8})}{2(12.56\times 10^{-7})}

B_{o} = 1.04\times 10^{-7} T

7 0
3 years ago
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