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Alexus [3.1K]
3 years ago
13

FIll in the blanks.: It's a beautiful day and you decide to go to the beach with some friends. The sun is ________

Physics
2 answers:
gregori [183]3 years ago
4 0
Converting
releases
absorbs
cooling
transfer
liberating
statuscvo [17]3 years ago
4 0
Converting
radiates
conducts
conducting
transfers some of
converting some of
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A race car moves along a circular track at a speed of 0.512 m/s. If the car's centripetal acceleration is 15.4 m/s2, what is the
tiny-mole [99]

Answer:

The radius is  r = 0.0170 \ m  

Explanation:

From the question we are told that

      The speed at which the race car moves is v  =  0.512 \ m/s

       The centripetal acceleration is  a _r  =  15.4 \ m/s

Generally the centripetal acceleration is mathematically represented as

           a_r =  \frac{v^2 }{r}

=>        15.4  =  \frac{0.512^2 }{ r}

=>       r = 0.0170 \ m  

 

6 0
3 years ago
Please answer fast..........​
Gnom [1K]

Answer:

The correct answer is a. Subsonic

Hope this helps you^_^

Please mark as Brainliest.

4 0
3 years ago
Read 2 more answers
Which of the diagrams below show forces that would result in a movement of the block to the left?
xenn [34]

Diagram A will result in the movement of the block to the left as a result of the forces.

<h3>What is Force?</h3>

This is referred to an influence which is capable of changing the motion of an object.

Diagram A has equal upward and downward force and left side which is 60N is higher than the right side which has 20N. The block will therefore move to the left.

Read more about Force here brainly.com/question/25239010

#SPJ1

4 0
2 years ago
Until he was in his seventies, Henri LaMothe excited audiences by belly-flopping from a height of 9 m into 32 cm. of water. Assu
baherus [9]

Answer:

823.46 kgm/s

Explanation:

At 9 m above the water before he jumps, Henri LaMothe has a potential energy change, mgh which equals his kinetic energy 1/2mv² just as he reaches the surface of the water.

So, mgh = 1/2mv²

From here, his velocity just as he reaches the surface of the water is

v = √2gh

h = 9 m and g = 9.8 m/s²

v = √(2 × 9 × 9.8) m/s

v = √176.4 m/s

v₁ = 13.28 m/s

So his velocity just as he reaches the surface of the water is 13.28 m/s.

Now he dives into 32 cm = 0.32 m of water and stops so his final velocity v₂ = 0.

So, if we take the upward direction as positive, his initial momentum at the surface of the water is p₁ = -mv₁. His final momentum is p₂ = mv₂.

His momentum change or impulse, J = p₂ - p₁ = mv₂ - (-mv₁) = mv₂ + mv₁. Since m = Henri LaMothe's mass = 62 kg,

J = (62 × 0 + 62 × 13.28) kgm/s = 0 +  823.46 kgm/s = 823.46 kgm/s

So the magnitude of the impulse J of the water on him is 823.46 kgm/s

6 0
3 years ago
Use the worked example above to help you solve this problem. A car traveling at a constant speed of 27.9 m/s passes a trooper hi
Sidana [21]
H h h huh h jvjvhvuvuvuvyv
7 0
3 years ago
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