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Ksivusya [100]
3 years ago
15

A gas at STP has a volume of 1.0 liter. If the pressure is doubled and the temperature remains constant, the new volume of the g

as will be...?
Chemistry
1 answer:
Aliun [14]3 years ago
5 0
PV = nRT

A gas at STP... This means that the temperature is 0°C and pressure is 1 atm.
R is the gas constant which is 0.08206 L*atm/(K*mol)

Rearranging for volume
V = nRT/P

The temperature and number of moles are held constant. This means that this uses Boyle's Law. (The ideal gas law could be manipulated to give us this result when T and n are held constant.)
PV = k
where k is a constant.

This means that
P₁V₁ = k = P₂V₂
P₁V₁ = P₂V₂

(1 atm) * (1 L) = (2 atm) * V₂
V₂ = 0.5 L

The new volume of the gas is 0.5 L.
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What is the limiting reagent when a 2.00 g sample of ammonia is mixed with 4.00 g of oxygen?​
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                      NH₃          :            N₂

                        4             :             2

                      0.12           :           2/4×0.12 = 0.06

                      NH₃         :            H₂O

                        4            :             6

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                       O₂            :            N₂

                        3             :             2

                      0.125        :           2/3×0.125 = 0.08

                        O₂           :            H₂O

                        3              :             6

                        0.125       :           6/3×0.125 = 0.25

The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.

Amount of oxygen left:

                        NH₃          :             O₂

                           4            :              3

                           0.12       :          3/4×0.12= 0.09

Amount of oxygen react = 0.09 mol

Amount of oxygen left  = 0.125 - 0.09 = 0.035 mol

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