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Anastaziya [24]
3 years ago
10

A cloud forms around 45Á south latitude and is carried through the atmosphere on the Westerlies, as shown below. As the water mo

lecules in the cloud move through the atmosphere, which step in the water cycle is most likely to happen next?
The molecules cool and eventually condense.
The molecules break apart and eventually evaporate.
The molecules heat up and eventually rise as water vapor.
The molecules combine and eventually fall as precipitation.
Chemistry
2 answers:
Molodets [167]3 years ago
3 0
Answer: fourth option: The molecules combine and eventually fall as precipitation.

In the cloud water is in the form of tiny, tiny drops. As the cloud gain more drops they will get in contact with each other, and due to the surface tension of water the drops will form bigger drops until the weight is too much and the drops fall as precipitation.
Gnesinka [82]3 years ago
3 0

Answer:

the answer is

The molecules combine and eventually fall as precipitation.

Explanation:

I took the test :v

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8 0
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When 40.5 g of Al and 212.7 g of Cl2 combine in the reaction: 2 Al (s) + 3 Cl2 (g) --> 2 AlCl3 (s) c) How many moles of the e
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Answer:

The answer to your question is 1.49 mol of Cl₂  

Explanation:

Data

mass of Al = 40.5 g

mass of Cl₂ = 212.7 g

moles of excess reactant = ?

- Balanced chemical reaction

                2 Al(s)  +  3Cl₂(g)  ⇒   2AlCl₃

Process

a) Calculate the molar mass of the reactants  

molar mass of Al = 2 x 26.98 = 53.96 g

molar mass of Cl₂ = 6 x 35.45 = 212.7 g

b) Calculate the theoretical proportion  Al/Cl₂ = 53.96/212.7 = 0.254

   Calculate the experimental proportion Al/Cl₂ = 40.5/212.7 = 0.19

As the experimental proportion is lower than the theoretical proportion we conclude that the limiting reactant is Aluminum.

c) Calculate the grams of excess reactant

                    53.96 g of Al ------------------ 212.7 g of Cl₂

                     40.5 g of Al -------------------  x

                      x = (40.5 x 212.7) / 53.96

                      x = 8614.35 / 53.96

                      x = 159.64 g of Cl₂

Excess Cl₂ = 212.7 - 159.64

                  = 53.057 g

d) Calculate the moles of Cl

                       35.45 g of Cl ----------------- 1 mol

                       53.057 g of Cl ---------------  x

                        x = (53.057 x 1)/35.45

                       x = 1.49 mol of Cl₂                    

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