D as it only has a negative effect when being used and it is small at that anyway.
<u>Answer:</u> The amount of water required to prepare given amount of salt is 398.4 mL
<u>Explanation:</u>
To calculate the volume of solution, we use the equation used to calculate the molarity of solution:
We are given:
Molarity of solution = 0.16 M
Given mass of manganese (II) nitrate tetrahydrate = 16 g
Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol
Putting values in above equation, we get:
Volume of water = Volume of solution = 398.4 mL
Hence, the amount of water required to prepare given amount of salt is 398.4 mL
Climate is considered an abiotic limiting factor because it is non living . hope this helped :))
Answer:
Base on the question , an acid and a base solution was mixed together in a crucible and all the water in the mixture was evaporated off. The only substance left in the crucible is the salt solution.
Explanation:
Acids are substances that dissolves in water to produce hydrogen ion(H⁺) while base are substances that dissolves in water to produce hydroxide ion (OH⁻).
The chemical reaction between an acid and a base solution is known as a neutralization reaction. The reaction between these 2 compounds will produce salt and water. An acid solution will react with a base solution to form salt and water. An example of this kind of reaction is between HCl (Hydrochloric acid) and NaOH(sodium hydroxide).
HCl + NaOH → NaCl + H₂O . The product form here is sodium chloride(salt) and water
Base on the question , an acid and a base solution was mixed together in a crucible and all the water in the mixture was evaporated off. The only substance left in the crucible is the salt solution. Note that the other product which is water has been evaporated and we are left with only salt solution.
