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4 years ago

11

Place value of 6 in 2.675 and 1 in 804.721

1 answer:

OleMash [197]4 years ago

3 0

1} 2.675 (6) =0.1 or the tenth

2} 804.721 (1) = 0.001 or the thousandth

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Use the graph to determine the true statement about the end behavior of the function

trasher [3.6K]

As the x-values got to + infinity, the function's values got to + infinity. This is a graph in which the positive end continues to go up indefinitely, meaning the function's values will end up becoming more and more positive as you go along the positive end of the x axis.

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4 years ago

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Using small pieces of construction paper, Sara makes a collage in the shape of a circle for art class. The diameter of the colla

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Diameter=d=8in

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3 years ago

If a polygon has four right angles, then it is either a square or a rectangle.

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B. A polygon is either a square or a rectangle

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3 years ago

We draw a random sample of size 36 from a population with standard deviation 3.5. If the sample mean is 27, what is a 95% confid

inessss [21]

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The 95% confidence interval for the population mean is between 25.86 and 28.14.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96\frac{3.5}{\sqrt{36}} = 1.14$

The lower end of the interval is the sample mean subtracted by M. So it is 27 - 1.14 = 25.86

The upper end of the interval is the sample mean added to M. So it is 27 + 1.14 = 28.14

The 95% confidence interval for the population mean is between 25.86 and 28.14.

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3 years ago

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Factor completely. x^4 - 9.

tester [92]

Answer:

$(x^2+3)(x^2-3)$

Step-by-step explanation:

Since both are perfect squares use the difference of squares formula $a^2-b^2=(a+b)(a-b)$ with a = $x^{2}$ and b = 3

= $(x^2 +3)(x^2-3)$

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4 years ago